我正在尝试将从RestSharp调用的JSON返回反序列化为API。
这是一个C#控制台应用程序。到目前为止,这是我的代码:
using System;
using RestSharp;
using RestSharp.Authenticators;
using Newtonsoft.Json.Linq;
using Newtonsoft.Json;
using RestSharp.Deserializers;
using System.Collections.Generic;
namespace TwilioTest
{
class Program
{
static void Main(string[] args)
{
var client = new RestClient("https://api.twilio.com/2010-04-01");
var request = new RestRequest("Accounts/{{Account Sid}}/Messages.json", Method.GET);
request.AddParameter("To", "{{phone number}}");
request.AddParameter("From", "{{phone number}}");
client.Authenticator = new HttpBasicAuthenticator("{{account sid}}", "{{auth token}}");
var response = client.Execute(request);
var jsonResponse = JsonConvert.DeserializeObject(response.Content);
Console.WriteLine(jsonResponse);
}
}
}
响应是一个JSON格式的邮件列表,其中的密钥包括"to"
,"from"
,"body"
和"status"
。这有点像:
{
"to": "{{phone number}}",
"from": "{{phone number}}",
"body": "Sent from your Twilio trial account - Message 1!",
"status": "delivered"
},
{
"to": "{{phone number}}",
"from": "{{phone number}}",
"body": "Sent from your Twilio trial account - Message 2",
"status": "delivered"
},
我希望将其转换为Message
个对象的数组,其中Message
类看起来像这样:
class Message
{
public string To { get; set; }
public string From { get; set; }
public string Body { get; set; }
public string Status { get; set; }
}
我一直在寻找如何将JSON转换为对象并找到此页面:http://blog.atavisticsoftware.com/2014/02/using-restsharp-to-deserialize-json.html。页面上的第三个例子与我想要的一致。
我对程序进行了一些更改,现在它看起来像这样:
class Program
{
static void Main(string[] args)
{
// same as above until this point
...
var response = client.Execute(request);
JsonDeserializer deserial = new JsonDeserializer();
var messageList = deserial.Deserialize<List<Message>>(response);
foreach (Message element in messageList)
{
Console.WriteLine("To: {0}", element.To);
Console.WriteLine("From: {0}", element.From);
Console.WriteLine("Body: {0}", element.Body);
}
Console.ReadLine();
}
}
但是,运行程序时messageList
为空。将JSON响应转换为对象列表,我错过了什么? RestSharp Documentation使它看起来相当简单。
答案 0 :(得分:3)
我对RestSharp了解不多,但你可以得到这样的响应内容字符串:
var responseContent = client.Execute(request).Content;
并使用Json.Net反序列化您的json字符串:
JObject jsonResponse = (JObject)JsonConvert.DeserializeObject(response.Content);
var messageList = JsonConvert.DeserializeObject<List<Message>>(jsonResponse["messages"].ToString());