Question

我的文档结构如下：

curl -XPUT 'http://localhost:9200/fin/deal/1' -d '
{ 
    "deal_key": "500029871", 
    "dealname": "Babson CLO Ltd. 2004-I", 
    "dealPct": "5" ,
    "mvdm": "5" ,
}'

curl -XPUT 'http://localhost:9200/blog/post/1' -d '
{ 
    "deal_key": "500029871", 
    "dealname": "Babson CLO Ltd. 2004-I", 
    "dealPct": "5" ,
    "mvdm": "5" ,
}'

curl -XPUT 'http://localhost:9200/blog/post/1' -d '
{ 
    "deal_key": "500029871", 
    "dealname": "Babson CLO Ltd. 2004-I2", 
    "dealPct": "5" ,
    "mvdm": "5" ,
}'

如何从弹性搜索中的查询中获取不同的记录集：我的查询如下：

 {
    "_source": [
    "dealname",
    "deal_key"
    ],
    "query": {
    "match": {
    "dealname": {
    "query": "Babson 2004",
    "operator": "and"
    }
    }
    }
    }

我回来的结果是：

"_source": {
"dealname": "Babson CLO Ltd. 2004-I",
"deal_key": "500029871"
}

"_source": {
"dealname": "Babson CLO Ltd. 2004-I",
"deal_key": "500029871"
}

"_source": {
"dealname": "Babson CLO Ltd. 2004-I2",
"deal_key": "500029871"
}

但是如你所见，输出中只有2个不同的记录

deal_key 500029871和dealname Babson CLO Ltd. 2004-I
deal_key 500029871和dealname Babson CLO Ltd. 2004-I2

但输出给了我3个结果集。我怎样才能改进这个？

在sql场景中，你可以假设我有一个包含4列的表，我试着在我的查询中只获得2列

select distinct col1 ,col2 from table1 where col2 = 'xyz'

在弹性搜索

0 个答案: