寻找另一个字符串中子串的出现

Question

我有两个MS SQL表：

如果第一表的字符串中的所有字符都包含在表二的字符串中，我必须说一个循环。

E.g。

 (_a_b_c_d_) is contained in (_a_c_b_d_) 

 (_a_b_) is contained in (_g_b_a_)

 (_a_f_d_) is not contained in (_a_c_b_d_)

希望你能帮忙！

由于

- 编辑

下划线是分隔符

这里的结果如下：

enter image description here

Answer 1

你可以试试这个：

DECLARE @xml1 xml, @xml2 xml

SELECT @xml1= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table1
FOR XML PATH('')
)

SELECT @xml2= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table2
FOR XML PATH('')
)

;WITH res1 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml1.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), res2 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml2.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), cte1 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res1 r WHERE r.id = r1.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res1 r1
), cte2 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res2 r WHERE r.id = r2.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res2 r2
)

SELECT t1.id as table1id, t2.id as table2id
FROM cte1 t1
INNER  JOIN cte2 t2 ON  t2.string LIKE '%'+t1.string+'%' --t1.string LIKE '%'+t2.string+'%' 
ORDER BY t1.id

结果：

table1id    table2id
----------- -----------
1           1
2           1
2           4
4           1
4           3

(5 row(s) affected)

我可以看到_a_b_中的_a_c_b_d_已被提及。