如何在oracle sql

Question

到目前为止，我做了类似的事情：

SELECT (EXTRACT(SECOND FROM (timeend  - timebeg))) AS diff 
FROM sometable HAVING diff > 5;

但它不能正常工作

Answer 1

请勿使用select

中where子句的字段别名

SELECT EXTRACT(second FROM (timeend  - timebeg)) AS diff 
FROM sometable 
WHERE EXTRACT(second FROM (timeend  - timebeg))> 5;

Answer 2

试试这个

Queue

这会在几秒钟内给出差异，您可以根据它进一步过滤您的查询。