Question

我试图让PHP将我的选择选项作为变量读取，然后根据用户选择回显特定页面。

登录系统功能正常但只能将我登录到一个页面。

<form action="login.php" method="POST">
    <table cellspacing="10">
        <tr>
            <td>Email: </td>
            <td><input type='text' name='email'/></td>
        </tr>
        <tr>
            <td>Password: </td>
            <td><input type='password' name='password'/></td>
        </tr>
        <tr>
            <td>Event: </td>
            <td>
                <select name="event">
                    <option><?php echo $title?></option>
                    <option><?php echo $title2?></option>
                </select>
            </td>
        </tr>
    </table>
    <br />
    <button class="button" type='submit' name='Submit' value='Submit' />Login</button> 
</form>

<?php

     if (!empty($email) && !empty($password)) {

                $pdo = getPdo();

                $statement = $pdo->prepare('SELECT * FROM awdawda WHERE email=:email;');

                $statement->bindParam(':email', $email);

                $statement->execute();

                $data = $statement->fetch();

                $pdo = null;

                if (!empty($data)) {
                    $dbemail = $data['email'];
                    $dbpassword = $data['password'];
                    $dbfullname = $data['fullname'];

                    if ($password == $dbpassword) {
                        $_SESSION['fullname'] = $dbfullname;
                        $_SESSION['email'] = $email;
                        $_SESSION['password'] = $password;

                        if ($_POST['event']) {
                            $event1=$title;
                            echo '<script type="text/javascript">window.location = "http://awda/adwa/awd1.php" </script>';
                        }

                        if ($_POST['event']) {
                            $event2=$title2;
                            echo '<script type="text/javascript">window.location = "http://awdaw/awda/adwa.php" </script>';
                        }

                    }

                    echo '<div style="padding: 10px;">Login Failed: Password Incorrect</div>';
                }

                echo '<div style="padding: 10px;">User not found</div>';
            }

?>

这是我用来登录的代码。我遗漏了它上面的东西，因为它现在一切正常。

Answer 1

您必须为options代码

的select赋予价值

<select name="event">
    <option value="value1"><?php echo $title?></option>
    <option value="value2"><?php echo $title2?></option>
</select>

并且必须根据这些值更新您的php逻辑

if ($_POST['event'] == "value1") {
    $event1=$title;
    echo '<script type="text/javascript">window.location = "http://awda/adwa/awd1.php" </script>';
}

if ($_POST['event'] == "value2") {
    $event2=$title2;
    echo '<script type="text/javascript">window.location = "http://awdaw/awda/adwa.php" </script>';
}

PHP重定向到基于select的表单提交页面

1 个答案: