Question

出于某种原因，我的联系表单的后端代码中一直出现错误

这是我的联系表格

  <div id = "form">

<form action ="contact2.php" method="post">
Hi Rebekah My Name Is
<br>
<input type="text" name="name">
<br>
My Email Is
<br>
<input type="text" name="email">
<br>
My Message Is
<br>
<TEXTAREA NAME="message" ROWS=6 COLS=40>
</TEXTAREA>

<br>

<input type="submit" value="Submit">

<?php 
include "contact2.php";
echo $result; 

?>

</div>

这是我的后端PHP代码

<?php

$field_name = $_POST['name'];
$email = $_POST['email'];
$field_message = $_POST['message'];

$mail_to = 'rebekahshaw92@yahoo.co.uk';

$subject = 'Message from a site visitor ' . $field_name;

$body_message = 'From: '.$field_name."\n";
$body_message .= 'E-mail: '.$email."\n";
$body_message .= 'Message: '.$field_message;

$headers = "From: $email\r\n";
$headers .= "Reply-To: $email\r\n";

$mail_status = mail($mail_to, $subject, $body_message, $headers);


// Check if name has been entered
if (!$_POST['name']) {

$field_name = 'Please enter your name';
}

// Check if email has been entered and is valid
if (!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
    $email = 'Please enter a valid email address';
}

//Check if message has been entered
if (!$_POST['message']) {
    $field_message = 'Please enter your message';
}

// If there are no errors, send the email
if (!$field_name && !$email && !$field_message) {
    if (mail ($_to, $subject, $body_message, $headers)) {
        $result='<div class="alert alert-success">Thank You! I will be in touch</div>';
    } else {
        $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later</div>';
    } 
?>

当我运行代码时，据说我的php代码在第43行是一个错误，这是最后一行，但我似乎无法看到问题是什么，因为这只是失败的标记PHP代码，当我拿出关闭php标签时，我仍然得到相同的消息。

以下是显示的消息。

解析错误：语法错误，第43行D：\ contact2.php中意外的文件结尾

出于安全原因，我已经从上面找到了文件的位置。

Answer 1

您的if (!$field_name && !$email && !$field_message) {未关闭。

Answer 2

您缺少if声明的结束标记。

在最后一行的结束标记}之前添加?>。

Answer 3

您上次的IF声明缺少}

if (!$field_name && !$email && !$field_message) {
    if (mail ($_to, $subject, $body_message, $headers)) {
        $result='<div class="alert alert-success">Thank You! I will be in touch</div>';
    } else {
        $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later</div>';
    }
} // <-----

带有解析错误的PHP联系表单

3 个答案: