我的客户，用户和收入类似于以下表格（实际上有数千条记录）：
Customer User Revenue
001 James 500
002 James 750
003 James 450
004 Sarah 100
005 Sarah 500
006 Sarah 150
007 Sarah 600
008 James 150
009 James 100
我想要做的只是返回占用户总收入80％的最高消费客户。
要手动执行此操作，我会按照收入计算詹姆斯的客户，计算总数百分比和运行总百分比，然后只返回记录，直至达到运行总计达到80％：
Customer User Revenue % of total Running Total %
002 James 750 0.38 0.38
001 James 500 0.26 0.64
003 James 450 0.23 0.87 <- Greater than 80%, last record
008 James 150 0.08 0.95
009 James 100 0.05 1.00
我尝试过使用CTE但到目前为止空白了。有没有办法通过单个查询而不是在Excel工作表中手动执行此操作？
答案 0 :(得分：7)
SQL Server 2012+
您可以使用窗口SUM：
WITH cte AS
(
SELECT *,
1.0 * Revenue/SUM(Revenue) OVER(PARTITION BY [User]) AS percentile,
1.0 * SUM(Revenue) OVER(PARTITION BY [User] ORDER BY [Revenue] DESC)
/SUM(Revenue) OVER(PARTITION BY [User]) AS running_percentile
FROM tab
)
SELECT *
FROM cte
WHERE running_percentile <= 0.8;
的 LiveDemo
SQL Server 2008：
WITH cte AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY Revenue DESC) AS rn
FROM t
), cte2 AS
(
SELECT c.Customer, c.[User], c.[Revenue]
,percentile = 1.0 * Revenue / NULLIF(c3.s,0)
,running_percentile = 1.0 * c2.s / NULLIF(c3.s,0)
FROM cte c
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM cte c2
WHERE c.[User] = c2.[User]
AND c2.rn <= c.rn) c2
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM cte c2
WHERE c.[User] = c2.[User]) AS c3
)
SELECT *
FROM cte2
WHERE running_percentile <= 0.8;
输出：
╔══════════╦═══════╦═════════╦════════════════╦════════════════════╗
║ Customer ║ User ║ Revenue ║ percentile ║ running_percentile ║
╠══════════╬═══════╬═════════╬════════════════╬════════════════════╣
║ 2 ║ James ║ 750 ║ 0,384615384615 ║ 0,384615384615 ║
║ 1 ║ James ║ 500 ║ 0,256410256410 ║ 0,641025641025 ║
║ 7 ║ Sarah ║ 600 ║ 0,444444444444 ║ 0,444444444444 ║
╚══════════╩═══════╩═════════╩════════════════╩════════════════════╝
编辑2：
看起来几乎在那里，唯一的麻烦就是它错过了最后一行， 詹姆斯的第三排让他超过0.80，但需要加入。
WITH cte AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY Revenue DESC) AS rn
FROM t
), cte2 AS
(
SELECT c.Customer, c.[User], c.[Revenue]
,percentile = 1.0 * Revenue / NULLIF(c3.s,0)
,running_percentile = 1.0 * c2.s / NULLIF(c3.s,0)
FROM cte c
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM cte c2
WHERE c.[User] = c2.[User]
AND c2.rn <= c.rn) c2
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM cte c2
WHERE c.[User] = c2.[User]) AS c3
)
SELECT a.*
FROM cte2 a
CROSS APPLY (SELECT MIN(running_percentile) AS rp
FROM cte2
WHERE running_percentile >= 0.8
AND cte2.[User] = a.[User]) AS s
WHERE a.running_percentile <= s.rp;
输出：
╔══════════╦═══════╦═════════╦════════════════╦════════════════════╗
║ Customer ║ User ║ Revenue ║ percentile ║ running_percentile ║
╠══════════╬═══════╬═════════╬════════════════╬════════════════════╣
║ 2 ║ James ║ 750 ║ 0,384615384615 ║ 0,384615384615 ║
║ 1 ║ James ║ 500 ║ 0,256410256410 ║ 0,641025641025 ║
║ 3 ║ James ║ 450 ║ 0,230769230769 ║ 0,871794871794 ║
║ 7 ║ Sarah ║ 600 ║ 0,444444444444 ║ 0,444444444444 ║
║ 5 ║ Sarah ║ 500 ║ 0,370370370370 ║ 0,814814814814 ║
╚══════════╩═══════╩═════════╩════════════════╩════════════════════╝
看起来很完美，翻译成我的大桌子并返回我需要的东西，花了5分钟完成它并且仍然无法完成你已经完成的工作！
SQL Server 2008不支持OVER()子句中的所有内容，但ROW_NUMBER不支持。
首先cte只计算一个组内的位置：
╔═══════════╦════════╦══════════╦════╗
║ Customer ║ User ║ Revenue ║ rn ║
╠═══════════╬════════╬══════════╬════╣
║ 2 ║ James ║ 750 ║ 1 ║
║ 1 ║ James ║ 500 ║ 2 ║
║ 3 ║ James ║ 450 ║ 3 ║
║ 8 ║ James ║ 150 ║ 4 ║
║ 9 ║ James ║ 100 ║ 5 ║
║ 7 ║ Sarah ║ 600 ║ 1 ║
║ 5 ║ Sarah ║ 500 ║ 2 ║
║ 6 ║ Sarah ║ 150 ║ 3 ║
║ 4 ║ Sarah ║ 100 ║ 4 ║
╚═══════════╩════════╩══════════╩════╝
第二个cte：
c2子查询根据ROW_NUMBER c3计算每位用户的总和在最终查询中s子查询找到的最低running总数超过80％。
编辑3：
使用ROW_NUMBER实际上是多余的。
WITH cte AS
(
SELECT c.Customer, c.[User], c.[Revenue]
,percentile = 1.0 * Revenue / NULLIF(c3.s,0)
,running_percentile = 1.0 * c2.s / NULLIF(c3.s,0)
FROM t c
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM t c2
WHERE c.[User] = c2.[User]
AND c2.Revenue >= c.Revenue) c2
CROSS APPLY
(SELECT SUM(Revenue) AS s
FROM t c2
WHERE c.[User] = c2.[User]) AS c3
)
SELECT a.*
FROM cte a
CROSS APPLY (SELECT MIN(running_percentile) AS rp
FROM cte c2
WHERE running_percentile >= 0.8
AND c2.[User] = a.[User]) AS s
WHERE a.running_percentile <= s.rp
ORDER BY [User], Revenue DESC;
答案 1 :(得分：0)
在SQL Server 2012+中，您将使用累积总和 - 效率更高。在SQL Server 2008中，您可以使用相关子查询或cross apply：
select t.*,
sum(t.Revenue*1.0) / sum(t.Revenue) over (partition by user) as [% of Total],
sum(RunningRevenue*1.0) / sum(t.Revenue) over (partition by user) as [Running Total %]
from t cross apply
(select sum(Revenue) as RunningRevenue
from t t2
where t2.Revenue >= t.Revenue and t2.user = t.user
) t2;
注意：*1.0只是在Revenue存储为整数的情况下。 SQL Server执行整数除法，它将为几乎所有行上的两列返回0。
编辑：
如果您只想为James提供结果，请添加where user = 'James'。