Sendgrid替换标签

时间:2016-04-06 08:39:25

标签: node.js coffeescript sendgrid substitution transactional-email

我想在我的应用程序中发送通知电子邮件,我正在尝试使用sendgrid。我的应用程序是在CoffeeScript中写的。

enter code here 
from_address = 'noreply@example.co'
subject = 'This Is The Subject'
html_body = '<table style="font-family: verdana, tahoma, sans-serif; color: #000;">
          <tr> <td>
          <h2>Hello,</h2> <p>Hello!!</p>
                          <p>%%name%% %%surname%% send you a message</p>
          </table>'
sendgrid = require('sendgrid')(api_key)
Email = sendgrid.Email
email = new Email(
  to: to_address
  from: from_address
  subject: subject
  text: text_body
  html: html_body)

recipients = [
  'example1@example.com'
  'example2@example.com'
]
i = 0
while i < recipients.length
  email.addTo recipients[i]
  i++

substitutions = {
  "%%name%%": [
    "name1",
    "name2"
  ],
  "%%surname%%": [
     "surname1",
     "surname2"
  ]
}

for tag in substitutions
  email.addSubstitution(tag, substitutions[tag])

email.setFilters({
  "templates": {
    "settings": {
      "enable": "1",
       "template_id": "XXXXXX-XXX-XXXX-XXXX-XXXXXXXXXX"
   }
 }
})


sendgrid.send email, (err, json) ->
  if err
    return console.log(err)
  console.log json
return

当我执行代码时,将电子邮件发送到电子邮件地址。但信息是:

您好!!

%% name %% %% surname %%会向您发送消息。

替换不起作用。我尝试将%%更改为%, - 和#。但任何那些似乎都有用。我也尝试使用setSections。

更新

这是我发送的sendgrid对象。

{ to: [ 'example1@example.com', 'example2@example.com' ],
  from: 'noreply@example.co',
  smtpapi: 
   { version: '1.2.0',
     header: 
      { to: [],
        sub: {},
        unique_args: {},
        category: [Object],
        section: {},
        filters: [Object],
        send_at: '',
        send_each_at: [],
        asm_group_id: {},
        ip_pool: '' } },
  subject: 'This Is The Subject',
  text: 'Hello!\n\nThis is a test message from SendGrid. We have sent this to you because you requested a test message be sent from your account.\n\n This is a link to google.com: http://www.google.com\n This is a link to apple.com: http://www.apple.com\n This is a link to sendgrid.com: http://www.sendgrid.com\n\n Thank you for reading this test message.\n\nLove,\nYour friends at SendGrid',
  html: '<table style="font-family: verdana, tahoma, sans-serif; color: #000;"> <tr> <td> <h2>Hello,</h2> <p>Hello!!</p> <p>%%name%% %%surname%% send you a message</p> </table>',
  bcc: [],
  cc: [],
  replyto: '',
  date: '',
  headers: {},
  toname: undefined,
  fromname: undefined,
  files: [] }

我做错了什么?

提前谢谢。

1 个答案:

答案 0 :(得分:0)

我回答了我自己的问题,因为已经找到了问题。

问题与Sendgrid有关,但与coffeeScript无关。在我的一个陈述中,我使用了这个:

for tag in substitutions
  email.addSubstitution(tag, substitutions[tag])

我在这里尝试向电子邮件对象添加替换标记。但是,在我的代码中,我发现循环并没有迭代替换变量。因此,任何标记都已添加到电子邮件对象中。

我已经更改了以前的代码:

Object.keys(substitutions).forEach((tag)->
  email.addSubstitution(tag, sub[tag])
  return

通过此更改,替换标记已添加到电子邮件对象中。