我正在尝试按日期对 json数据进行排序,但它无效。这是我正在尝试的。请纠正我错误的地方
示例代码
var temp = [{
"id": 17608,
"title": "abc",
"start": "2016-03-23 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "def",
"start": "2016-04-13 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "ghi",
"start": "2016-04-08 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}];
console.log(temp);
temp.sort(function(a, b) {
if (new Date(a.start) == new Date(b.start)) {
return a.row == b.row ? 0 : +a.row > +b.row ? 1 : -1;
}
return new Date(a.start) > (b.start) ? 1 : -1;
});
console.log(temp);
答案 0 :(得分:6)
您可以使用日期字符串进行排序,而日期为ISO 6801。
var temp = [{ "id": 17608, "title": "abc", "start": "2016-03-23 06:13:00.0", "backgroundColor": "#000000", "borderColor": "#000000", "textColor": "#fff" }, { "id": 17608, "title": "def", "start": "2016-04-13 06:13:00.0", "backgroundColor": "#000000", "borderColor": "#000000", "textColor": "#fff" }, { "id": 17608, "title": "ghi", "start": "2016-04-08 06:13:00.0", "backgroundColor": "#000000", "borderColor": "#000000", "textColor": "#fff" }];
temp.sort(function (a, b) {
return a.start.localeCompare(b.start);
});
document.write("<pre>" + JSON.stringify(temp, 0, 4) + "</pre>");
&#13;
答案 1 :(得分:2)
比较日期时应使用date.getTime()
。
var temp= [{id:17608,title:"abc",start:"2016-03-23 06:13:00.0",backgroundColor:"#000000",borderColor:"#000000",textColor:"#fff"},{id:17608,title:"def",start:"2016-04-13 06:13:00.0",backgroundColor:"#000000",borderColor:"#000000",textColor:"#fff"},{id:17608,title:"ghi",start:"2016-04-08 06:13:00.0",backgroundColor:"#000000",borderColor:"#000000",textColor:"#fff"}];
console.log(temp);
temp.sort(function(a, b) {
var d1 = new Date(a.start).getTime();
var d2 = new Date(b.start).getTime();
return d1<d2?-1:d1>d2?1:0;
});
console.log(temp);
&#13;
答案 2 :(得分:2)
您的代码很好,只是因为您在比较中错过了第二个new Date()
:
return new Date(a.start) > (b.start) ? 1 : -1;
应该是:
return new Date(a.start) > new Date(b.start) ? 1 : -1;
现在的方式,您只需将Date
对象与string
进行比较。
答案 3 :(得分:2)
实现这一目标有多种方法。其中,最简单的方法是将字符串转换为日期并将它们相互减去以获得负数,正数或零数:
temp.sort(function(a,b){
return new Date(a.start) - new Date(b.start);
});
通常认为sort函数需要返回-1
,1
或0
。这是不正确的。它将根据数字是正面,否定或零来对项目进行排序。 ECMAScript specification将其声明为:
如果comparefn未定义,则它应该是一个接受两个参数x和y的函数,如果x&lt;则返回负值。 y,如果x = y则为零,或者如果x> y则为正值;收率
完整示例:
var temp = [{
"id": 17608,
"title": "abc",
"start": "2016-03-23 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "def",
"start": "2016-04-13 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "ghi",
"start": "2016-04-08 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}];
console.log(temp);
temp.sort(function(a,b){
// Convert strings to dates and substract.
// This way you get a value which is negative, positive or zero
return new Date(a.start) - new Date(b.start);
});
console.log(temp);
答案 4 :(得分:-1)
var temp = [{
"id": 17608,
"title": "abc",
"start": "2016-03-23 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "def",
"start": "2016-04-13 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}, {
"id": 17608,
"title": "ghi",
"start": "2016-04-08 06:13:00.0",
"backgroundColor": "#000000",
"borderColor": "#000000",
"textColor": "#fff"
}];
console.log(temp);
temp.sort(function(a, b) {
return parseFloat(a.start) - parseFloat(b.start);
});
console.log(temp);