Question

我知道标题有点模糊，但是我正在制作一个掷骰子的程序（因为你在课程中永远都看到过），令我困惑的是我的输出结果。

我只是滚动一个六面骰子并计算每张脸的出现次数。我的结果打印出列表形式的ID，但是当我告诉程序滚动说30次时，我收到的结果是-858993460。我不知道它可能来自哪里，我希望有人可以告诉我出错的地方，发布我的标题和源文件代码，其中一些在我留下评论的某些区域是不完整的。< / p>

//Dice.h
#pragma once
#include <iostream>

使用namespace std;

class aDie {
public:
    aDie();
    int Roll();
    int getRoll();
    void setRolls(int r);
    int getTotal();
    void setTotal(int t);
    int numOnes = 0, numTwos = 0, numThrees = 0, numFours = 0, numFives = 0, numSixes = 0;
    int rollTotal();
    int Display();
    int numRolls;
    int allRolls = 0;
    int randomRoll;
protected:
    int roll;
    int totalRoll;
    int DisplaySomeRolls;

};

aDie::aDie() {

}

int aDie::getRoll() {
    return roll;

}

void aDie::setRolls(int r) {
    roll = r;
}

int  aDie::getTotal() {
    return  totalRoll;
}

void aDie::setTotal(int t) {
    totalRoll = t;
}

int aDie::Roll() {
    //roll the dice here
    return 0;
}

int aDie::Display() {
    int DiceFaces[6]  { numOnes, numTwos, numThrees, numFours, numFives, numSixes };

return DisplaySomeRolls;
    //use this to display the outputs of each face
}

// ProjectNumberTwo.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include <ctime>
#include <cstdlib>
#include "Dice.h"
using namespace std;

int main(){
    aDie getRolls;
    aDie DiceFaces[6];
    int  numRolls    = 0;
    int  rollTotal   = 0;
    int  numOnes     = 0, numTwos = 0, numThrees = 0, numFours = 0, numFives = 0, numSixes = 0;
    int  randomRoll  = rand() % 6 + 1;


    srand((unsigned int)time(NULL));

    cout << "How many rolls? "; // GEt user input of how many rolls
    cin >> numRolls;
    cin.ignore();


    cout << "**Dice Roll Statistics***" << endl;

    getRolls.setRolls(numRolls);


    if (numRolls >= 1) {  // Rolls dice numRolls times
        for (int i = 0; i < 6; i++) //makes a for-loop that makes an array of all the rolls from the user input
            DiceFaces[i].setRolls(randomRoll);

        numRolls = randomRoll;

        if (rollTotal == 1) { // Count number of occurences 1-6
            numOnes += 1;
        }
        else if (rollTotal == 2) {
            numTwos += 1;
        }
        else if (rollTotal == 3) {
            numThrees += 1;
        }
        else if (rollTotal == 4) {
            numFours += 1;
        }
        else if (rollTotal == 5) {
            numFives += 1;
        }
        else if (rollTotal == 6) {
            numSixes += 1;
        }
    }

    for (int i = 1; i < 6; i++)
        cout << i << ": " << DiceFaces[i].Display() << endl;


    // The printout needs to be rollFaces so it prints how many times the face  
    // happened, not getroll which only shows one single roll

    system("pause");
    return 0;
}

Answer 1

你为什么这样做：

numRolls = randomRoll;

此外，请查看您设置模具滚动的内容以及进行随机滚动分配的时间。

老实说，你使用的逻辑似乎比它需要的复杂得多。你的代码很天真，我建议你从头开始（没有冒犯）。写一些代码将10个骰子卷分配给你的计数器，然后从那里扩展，（不要害怕破坏者）。

我希望这会有所帮助。

Answer 2

尝试一下，让我知道它是否适合您！

#include<iostream>
#include<stdlib.h>
using namespace std;
class dice
{
public:
    int a,z=0,y=0,x=0,w=0,v=0,u=0;
    void number_generation()
    {
        a=rand()%6+1;
    }
    void checkcount(int t)
    {
        if(t==1)z++;
        else if(t==2)y++;
        else if(t==3)x++;
        else if(t==4)w++;
        else if(t==5)v++;
        else u++;
    }
    void display()
    {
        cout<<"OCCURENCE OF EACH NUMBER IS AS FOLLOWS:\n";
        cout<<"1-"<<z<<endl<<"2-"<<y<<endl<<"3-"<<x<<endl<<"4-"<<w<<endl<<"5-"<<v<<endl<<"6-"<<u<<endl;
    }
};
int main()
{
    int i,throws;
    dice d;
    cout<<"Enter the number of throws";
    cin>>throws;
    for(i=0;i<throws;i++)
    {
        d.number_generation();
        d.checkcount(d.a);
    }
    d.display();
}

从滚动打印的负数结果

2 个答案: