Question

我想知道如何在mongodb中只使用其名称的最后三个字母找到一些东西，结构为db.collection.find（），谢谢！

  {  
    "address": {
      "building": "1007",
      "coord": [ -73.856077, 40.848447 ],
      "street": "Morris Park Ave",
      "zipcode": "10462"
    },
    "borough": "Bronx",
    "cuisine": "Bakery",
    "grades": [
      { "date": { "$date": 1393804800000 }, "grade": "A", "score": 2 },
      { "date": { "$date": 1378857600000 }, "grade": "A", "score": 6 },
      { "date": { "$date": 1358985600000 }, "grade": "A", "score": 10 },
      { "date": { "$date": 1322006400000 }, "grade": "A", "score": 9 },
      { "date": { "$date": 1299715200000 }, "grade": "B", "score": 14 }
    ],  
    "name": "Morris Park Bake Shop",
    "restaurant_id": "30075445"
  }

我目前的尝试：

db.mycollection.find({},{name:"ces"})

Answer 1

取决于您是指＆＃34;单词＆＃34; 或＆＃34;的最后三个字母，＆＃39;＆＃39;＆＃34; 那么你通常需要一个$regex

关于这些数据：

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }
{ "_id" : ObjectId("5704624d8c0fd5187b53985b"), "name" : "Something" }
{ "_id" : ObjectId("5704625b8c0fd5187b53985c"), "name" : "Bounces Something" }

然后查询＆＃34;字＆＃34;，其中\b表示＆＃34;字边界＆＃34;，并在＆＃34;字符串＆＃中由\转义34;表达式：

db.collection.find({ "name": { "$regex": "ces\\b" } })

匹配：

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }
{ "_id" : ObjectId("5704625b8c0fd5187b53985c"), "name" : "Bounces Something" }

或查询＆＃34;字段＆＃34;，其中$表示＆＃34;从最后＆＃34;：

db.collection.find({ "name": { "$regex": "ces$" } })

匹配：

{ "_id" : ObjectId("570462448c0fd5187b53985a"), "name" : "Bounces" }

Answer 2

尝试以下任何一种方法

：

db.mycollection.find({name: /ces$/})
db.hotels.find({name: {$regex: "ces$"}})
db.hotels.find({name: {$regex: /ces$/}})

匹配字符串＆＃34; ces＆＃34;在最后三封信中

2 个答案: