Question

这是我到目前为止所得到的但是由于某种原因，程序声明操作完成而不允许用户输入1或2继续或不继续。提前谢谢..

我的代码：

import java.util.Random;
public final class Kidwell_Lab09 {
    public static Random generator = new Random();
    public static void main(String[] args) {
        int x;

        int[] randomNumbers = new int[20];

        do
        {
            Random generator = new Random();
            for (int i = 0; i < randomNumbers.length; i++){
                int n = generator.nextInt(10)+1;
                randomNumbers[i] = n;
            }

            for (int i = 0; i < randomNumbers.length; i++) {
                System.out.println("Number " + i + " : " + randomNumbers[i]);
            }
            System.out.print("Do you wish to restart the program, Enter 1 for YES, 2              for NO: ");
            x = generator.nextInt();
        }
        while ( x == 1 );
    }
}

Answer 1

您应该从System.in而不是从generator.nextInt（）读取值。

这是更正后的代码。

import java.util.Random;
public final class Kidwell_Lab09 {
    public static Random generator = new Random();

    public static void main(String[] args) {
        int x;

        int[] randomNumbers = new int[20];
        Scanner inputReader = new Scanner(System.in);
        do {
            Random generator = new Random();
            for (int i = 0; i < randomNumbers.length; i++) {
                int n = generator.nextInt(10) + 1;
                randomNumbers[i] = n;
            }

            for (int i = 0; i < randomNumbers.length; i++) {
                System.out.println("Number " + i + " : " + randomNumbers[i]);
            }
            System.out.print("Do you wish to restart the program, Enter 1 for YES, 2              for NO: ");            
            x = inputReader.nextInt();
        } while (x == 1);
    }    
}

使用由Sentinel驱动的外部While循环来询问用户是否希望生成一组新的随机数

1 个答案: