Question

我正在尝试定义自己的自定义模板，以便在输入时输入：

var bazs = new List<Baz> {
    new Baz {
        Id = 1,
        StartDate = DateTime.Today,
        EndDate = DateTime.Today.AddMonths(1)
    },
    new Baz {
        Id = 2,
        StartDate = DateTime.Today.AddMonths(-1),
        EndDate = DateTime.Today.AddMonths(1)
    },
    new Baz {
        Id = 3,
        StartDate = DateTime.Today,
        EndDate = DateTime.Today.AddMonths(1)
    }
};

List<Foo> foos = new List<Foo>{
    new Foo
    {
        EmployeeId = 1,
        CompanyId = 2,
        GroupId = 3,
        Bars = new List<Bar> {
            new Bar { BazId = 1 },
            new Bar { BazId = 2 },
            new Bar { BazId = 3 }
        }
    }
};

var result = (from extendedBar in foos.SelectMany(f => f.Bars.Select(b => new { Bar = b, f.EmployeeId, f.CompanyId, f.GroupId }))
              join baz in bazs
              on extendedBar.Bar.BazId equals baz.Id
              select new { extendedBar.Bar, extendedBar.EmployeeId, extendedBar.CompanyId, extendedBar.GroupId, baz.StartDate, baz.EndDate })
                .GroupBy(o => new { o.EmployeeId, o.CompanyId, o.GroupId, o.StartDate, o.EndDate })
                .Select(g => new Foo { EmployeeId = g.Key.EmployeeId, CompanyId = g.Key.CompanyId, GroupId = g.Key.GroupId, Bars = g.Select(o => o.Bar).ToList() })
             .ToList();

它会吐出以下的html

@inputText(
  myForm("firstName"),
  '_label -> "First Name"
)

Answer 1

您需要创建自定义fieldConstructorTemplate。

创建名为<urname>.scala.html

然后在那里写下面的代码：

@(elements: helper.FieldElements)
<div class="form-group">
  <label class="col-lg-12" for="@elements.id">@elements.label</label>
  <div class="col-sm-9">
   <input type="text" class="form-control" name="@elements.field.name"
    value="@elements.field.value"></input>
 </div>

接下来在scala模板中使用：

@inputText( myForm("firstName"), '_label -> "First Name")

@implicitField = @{ FieldConstructor(yourFieldConstructorTemplateName.f) }

自定义Scala表单模板

1 个答案: