Question

这似乎应该非常直接 - 但是，唉，我遇到了崩溃。我只是尝试使用 users_name 字段返回的文本设置我的UILabel：

的.m

NSMutableDictionary *viewParams = [NSMutableDictionary new];
[viewParams setValue:@"u000" forKey:@"view_name"];
[DIOSView viewGet:viewParams success:^(AFHTTPRequestOperation *operation, id responseObject) {


   self.userData = [responseObject mutableCopy];

   self.username.text = [self.userData objectForKey:@"users_name"];

   dispatch_async(dispatch_get_main_queue(), ^(void){

    });


} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Failure: %@", [error localizedDescription]);
}];

控制台数据返回：

2016-04-05 12:25:36.877 [1331:350069] This is the Other User Data (
        {
        address = "Vancouver";
        userbio = "There is currently no bio available for this user. If you have added your bio, and require assistance, please contact the  Team.";
        "users_name" = Brittany;
    },

那就是说，这条线导致了崩溃：

self.username.text = [self.userData objectForKey:@"users_name"];

这是错误：

2016-04-05 12：25：36.878 [1331：350069] - [__ NSCFArray objectForKey：]：无法识别的选择器发送到实例0x15a23c100 2016-04-05 12：25：36.881 [1331：350069] *由于未被捕获而终止应用异常＆＃39; NSInvalidArgumentException＆＃39;，原因：＆＃39; - [__ NSCFArray objectForKey：]：无法识别的选择器发送到实例0x15a23c100＆＃39; * 第一次抛出调用堆栈：（0x181d51900 0x1813bff80 0x181d5861c 0x181d555b8 0x181c5968c 0x1000cce9c 0x1000c72bc 0x1000d3cc4 0x100459bf0 0x100459bb0 0x10045f658 0x181d08bb0 0x181d06a18 0x181c35680 0x183144088 0x186aacd90 0x1000d4c88 0x1817d68b8） libc ++ abi.dylib：以未捕获的类型异常终止 NSException

我该如何解决这个问题？看起来应该很简单......

Answer 1

我认为and是一种数组类型。数组没有键值。尝试：
userData

由于未被捕获而终止应用程序＆gt;异常＆＃39; NSInvalidArgumentException＆＃39;

1 个答案: