在我一直在努力的当前页面上,我已经将代码设置为可以作为实时博客/更新类型的系统使用。问题是,我在我的PHP中从我的数据库加载了东西,然后我有AJAX链接到另一个文件,它将获取数据库内容并刷新它包含在我的网站上的区域。
因此'这意味着它将使用数据库中的数据每15000毫秒自动更新一次。问题是,它已经加载了现有数据。所以无论如何。每15000毫秒,它将刷新该div,因此页面上已有的数据将被复制。
更多Clear Bulletpoint表格
我只是真正进入PHP,我没有花太多时间,而且我对AJAX的了解并不存在,所以它会出现这样的问题。我已尝试搜索如何仅回显第一页上的现有数据,即使第二页正在处理更新。
然而,这是代码,如果它很乱,或者说正确的话,请对不起。我还在学习这门语言。
第一页matchdayupdates.php?id =(在这种情况下,id为6)
$id = $_GET['id'];
if(isset($_GET['id'])) {
$requestMatchInformation = mysqli_query($connect, "SELECT * FROM matchinfo WHERE pageid='$id' LIMIT 500");
while ($row = mysqli_fetch_assoc($requestMatchInformation)) {
$pageid = $row['pageid'];
$type = $row['type'];
$postheader = $row['postheader'];
$postcontent = $row['postcontent'];
$posttime = $row['posttime'];
echo "<div class='center-match-container'>
<div class='match-information'>
<div class='post-container'>
<div class='post-left'>
<img class='post-type-icon' src='images/icons/$type' />
</div>
<div class='post-right'>
<h3 class='header-top'>$postheader</h3>
<span class='time-red-right'>$posttime</span>
<br />
<br />
<p class='post-content'>$postcontent</p>
</div>
</div>
</div>
</div>";
}
$requestEventsInformation = mysqli_query($connect, "SELECT * FROM events WHERE id='$id'");
while($row = mysqli_fetch_assoc($requestEventsInformation)) {
$opponent = $row['opponent'];
$datetime = $row['datetime'];
$datetimedisplay = $row['datetimedisplay'];
$location = $row['location'];
$datepassed = $row['datepassed'];
$rowonescore = $row['rowonescore'];
$rowtwoscore = $row['rowtwoscore'];
$rowoneplayers = $row['rowoneplayers'];
$rowtwoplayers = $row['rowtwoplayers'];
}
}
else {
}
if(!$requestEventsInformation && !$requestMatchInformation) {
echo '<div class="match-notice"><h4>There are currently no updates, this page will auto-update when there are new updates.</h4></div>';
}
echo $id;
?>
<script>
var auto_refresh = setInterval(function () {
$('.center-match-container').fadeOut('slow', function() {
$(this).load('/esports/match/matchinforequest.php?id=<?php echo $id; ?>', function() {
$(this).fadeIn('slow');
});
});
$.ajaxSetup({ cache: true });
}, 15000);
</script>
&#13;
第二页matchinforequest.php?id =(同样这个id是6)
$id = $_GET['id'];
if(isset($_GET['id'])) {
$requestMatchInformation = mysqli_query($connect, "SELECT * FROM matchinfo WHERE pageid='$id' LIMIT 500");
while ($row = mysqli_fetch_assoc($requestMatchInformation)) {
$pageid = $row['pageid'];
$type = $row['type'];
$postheader = $row['postheader'];
$postcontent = $row['postcontent'];
$posttime = $row['posttime'];
echo "<div class='center-match-container'>
<div class='match-information'>
<div class='post-container'>
<div class='post-left'>
<img class='post-type-icon' src='images/icons/$type' />
</div>
<div class='post-right'>
<h3 class='header-top'>$postheader</h3>
<span class='time-red-right'>$posttime</span>
<br />
<br />
<p class='post-content'>$postcontent</p>
</div>
</div>
</div>
</div>";
}
$requestEventsInformation = mysqli_query($connect, "SELECT * FROM events WHERE id='$id'");
while($row = mysqli_fetch_assoc($requestEventsInformation)) {
$opponent = $row['opponent'];
$datetime = $row['datetime'];
$datetimedisplay = $row['datetimedisplay'];
$location = $row['location'];
$datepassed = $row['datepassed'];
$rowonescore = $row['rowonescore'];
$rowtwoscore = $row['rowtwoscore'];
$rowoneplayers = $row['rowoneplayers'];
$rowtwoplayers = $row['rowtwoplayers'];
}
echo "Received Data";
}
else {
}
&#13;
答案 0 :(得分:0)
问题是你要将新数据加载到类center-match-container
的任何HTML元素中,但是你用AJAX获得的新数据也包含一个类center-match-container
的元素,所以第二个call将它加载到两个地方,依此类推。
在matchinforequest.php
移除<div class='center-match-container'>
和相应的</div>
,它应该有效。
作为旁注,您没有使用预准备语句,而是将$ _GET [&#39; id&#39;]的内容直接放入数据库查询中。这意味着有人可以通过将id
设置为0'; DELETE FROM matchinfo; '
来轻松擦除数据库。请查看准备好的语句http://php.net/manual/en/mysqli.prepare.php并更新您的代码以避免此安全风险!