Question

我在将SQL语句转换为CodeIgniter查询构建器记录时遇到问题。在工作台中，我运行以下查询没有问题。

这适用于MySQL WorkBench ......

# This 
SELECT DISTINCT
    projects.id, projects.title
FROM
    projects
INNER JOIN
    positions
ON
    (projects.id = positions.project_id)
WHERE (positions.is_draft = '0')

查询构建器

$this->db->select('DISTINCT projects.id, projects.title');
$this->db->from('projects');
$this->db->join('positions', 'projects.id = positions.project_id', 'inner');
$this->db->where('positions.is_draft', '0');
$query = $this->db->get();

return $query->result();

错误

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.`id`, `projects`.`title` FROM `projects` INNER JOIN `positions` ON `projects`.`' at line 1

SELECT `DISTINCT` `projects`.`id`, `projects`.`title` FROM `projects` INNER JOIN `positions` ON `projects`.`id` = `positions`.`project_id` WHERE `positions`.`is_draft` =0

我也试过

$this->db->where('positions.is_draft = 0');

我认为问题在于平等分配，但你怎么看？我玩过它，但不断得到同样的错误。

Answer 1

可能与 distinct（）有关。在Codigniter中有几种使用distinct的方法。

$this->db->distinct();

或在您的示例中尝试此

$this->db->select('DISTINCT(projects.id), projects.title');

codeigniter查询构建器数据库错误相等

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