Question

您好我已经使用java创建了一个测验应用程序，但我不确定如何实现这个小部分。它要求我： 如果用户输入一个字符，即'a'

，则添加例外以捕获NumericQuestion类型上的NumberFormatException

我最初尝试在presentQuestion方法的开头插入一个try catch块，但它给我带来了很多错误。我没有太多实施这些try-catch方法的经验。我知道它可能很简单，所以任何帮助都会受到欢迎。我的代码如下所示。

package QuestionGame;

import java.util.Scanner;

public class NumericQuestionTester {

    public static void main(String[] args) {
        boolean userCorrect;
        Scanner input = new Scanner(System.in);
        NumericQuestion quThree = new NumericQuestion("What is the answer to 5 divided by 3?", "1.67", 2, 0.03, 0.07);
        presentQuestion(input, quThree);
        input.close();

    }

    public static void presentQuestion(Scanner input, NumericQuestion q) {
        boolean userCorrect;
        q.displayQuestion();
        System.out.println("Enter your answer: ");
        String answer = input.nextLine();
        userCorrect = q.checkAnswer(answer);
        if (userCorrect){
            System.out.println("Correct! The answer is : " + q.getAnswer() + " and you have a score of : " + q.getMark());
        } else {
            System.out.println(answer + " is incorrect. You scored zero.");
        }
        System.out.println();
    }
}


package QuestionGame;

public class NumericQuestion extends Question {

    //instance variables
    private double ansNumeric;
    private double positiveRange;
    private double negativeRange;

    //constructor
    public NumericQuestion(String quText, String answer, int mark, double positiveRange, double negativeRange) {
        super(quText, answer, mark);
        this.ansNumeric = Double.parseDouble(answer);
        this.positiveRange = positiveRange;
        this.negativeRange = negativeRange;
    }

    //accessors & mutators
    public double getAnsNumeric() {
        return ansNumeric;
    }

    public void setAnsNumeric(double ansNumeric) {
        this.ansNumeric = ansNumeric;
    }

    //methods

    public boolean checkAnswer (String answer) {
        double answerDouble = Double.parseDouble(answer);
        if (answerDouble > (this.ansNumeric + this.positiveRange)) {
            return false;
        } else if (answerDouble < (this.ansNumeric - this.negativeRange)) {
            return false;
        } else {
            return true;
        }
    }

}

Answer 1

除exception处理之外，我建议您添加持久性检查，而用户不会放置预期的整数答案。

do{
     System.out.println("You Numeric answer, please")
     String answer = input.nextLine();
}while !answerIsNumeric(answer);
userCorrect = q.checkAnswer(answer);

public boolean answerIsNumeric(String answer){
     try{
         Double.parseDouble(answer);
     }catch(NumberFormatException e){
         return false;
     }
     return true;
}

Answer 2

根据应用程序设计，有很多方法可以实现这一目标。我会在这里向您展示一个 - 如果不适用，请提供更多细节，不过我想这就是您要找的东西

public static void presentQuestion(Scanner input, NumericQuestion q) {
        boolean userCorrect = false;
        boolean isAnswerNumeric = false;
        String answer = null;
        while(! isAnswerNumeric){
            q.displayQuestion();
            System.out.println("Enter your answer (numeric only) : ");
            answer = input.nextLine();
            try{
                Double.parseDouble(answer);
                isAnswerNumeric = true;
            }catch(NumberFormatException nfe){
               // do nothing in this case.. if the number format is correct, 
               // the isAnswerNumeric will be set to true
            }
        }
        userCorrect = q.checkAnswer(answer);
        if (userCorrect){
            System.out.println("Correct! The answer is : " + q.getAnswer() + " and you have a score of : " + q.getMark());
        } else {
            System.out.println(answer + " is incorrect. You scored zero.");
        }
        System.out.println();
}

您可以调整代码以显示错误消息或您想要在catch块中执行的任何操作。在这种情况下，作为一个简单的例子，问题会被再次询问，直到答案是数字

Answer 3

您可能只需要将answer字符串解析为Float.parseFloat的数字并抓住NumberFormatException。

示例：

    String answer = "3.14";

    try {

        float numericAnswer = Float.parseFloat(answer);

        System.out.println("numericAnswer=" + numericAnswer);

    } catch (NumberFormatException e) {

        System.err.println(answer + " is not a number.");
    }

如果通过添加异常来捕获NumberFormatException - 这句话没有多大意义 - 它们意味着抛出异常，只需添加catch块

throw new WhateverException(answer + " is not a number.");（f.ex。你可以抛出RuntimeException）。

java在Numeric类型上捕获NumberFormatException

3 个答案: