Question

这是我试图运行的查询：

＆＃13;

{ ownerId: 14,
  '$or': 
   [ { '$or': 
        [ { '$and': 
             [ { provider: 'INSTAGRAM' },
               { tags: 
                  { '$or': 
                     [ { '$in': [ 'skyhotel' ] },
                       { '$or': [ { '$all': ["skyhotel","excellent"] } ] } ] } } ] },
          { '$and': 
             [ { provider: 'VKONTAKTE' },
               { tags: 
                  { '$or': 
                     [ { '$in': [ 'skyhotel' ] },
                       { '$or': [ { '$all': ["skyhotel","excellent"] } ] } ] } } ] } ] },
     { '$or': 
        [ { '$and': 
             [ { provider: 'INSTAGRAM' },
               { authorLogin: { '$in': [ 'valera92', 'petyan' ] } } ] },
          { '$and': 
             [ { provider: 'VKONTAKTE' },
               { authorLogin: { '$in': [ 'valera92' ] } } ] } ] },
     { '$or': 
        [ { '$and': 
             [ { provider: 'INSTAGRAM' },
               { locationId: { '$in': [ '32454234' ] } } ] } ] },
     { '$or': 
        [ { '$and': 
             [ { provider: 'INSTAGRAM' },
               { location: { '$or': [ { '$geoWithin': { '$centerSphere': [ [ '56.829782', '60.593162' ], 0.000012629451881788331 ] } } ] } } ] } ] } ] }

＆＃13;

根据mongo标准，它似乎是畸形的。我得到的错误是：

Can't canonicalize query: BadValue unknown operator: $or

我可以通过哪种方式重新格式化此查询？

编辑：文档示例

＆＃13;

{
    "_id" : ObjectId("570362332ee1a7ab1ecb9899"),
    "proextid" : "INSTAGRAM_fdfsfsdfsdfwefwef2r3232",
    "updatedAt" : ISODate("2016-04-05T06:58:59.683Z"),
    "createdAt" : ISODate("2016-04-05T06:58:59.683Z"),
    "ownerId" : 7,
    "authorId" : "390599885",
    "authorName" : "name",
    "authorLogin" : "login",
    "authorDetail" : {
        "authorPicture" : "url",
        "authorLink" : "url"
    },
    "externalCreatedAt" : ISODate("2015-08-29T22:42:04.000Z"),
    "externalId" : "fdsfsdfsdfsdfwer2342342423423r23r",
    "detailType" : "PHOTO",
    "location" : [ 
        0, 
        0
    ],
    "locationId" : "",
    "locationTitle" : "",
    "provider" : "INSTAGRAM",
    "detail" : {},
    "description" : "hello",
    "tags" : [ 
        "ленинградскийпроспект", 
        "москва", 
        "архитектура", 
        "историческоенаследие", 
        "петровскийдворец"
    ],
    "commentsCount" : 1,
    "likesCount" : 40,
    "groupName" : "",
    "__v" : 0
}

＆＃13;

Answer 1

您的查询可以简化为：

<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>JSP Page</title>

        <script>
            var count=0;
            function addRow(tableId)
            {
                count++;
                var element1=document.getElementById(tableId);
                var tr=document.createElement("tr");
                tr.id="row"+count;

                var td1=document.createElement("td");
                var td2=document.createElement("td");
                var td3=document.createElement("td");

                td1.innerHTML="row"+count+" col 1";
                td2.innerHTML="row"+count+" col 2";
                td3.innerHTML="row"+count+" col 3";

                tr.appendChild(td1);
                tr.appendChild(td2);
                tr.appendChild(td3);

                element1.appendChild(tr);

                alert('row'+count);
            }
            function removeRow(tableId)
            {
                var element1=document.getElementById(tableId);
                var row=document.getElementById('row'+count);
                alert('row'+count);
                element1.removeChild(row);
                count--;
            }
        </script>

    </head>
    <body>
        <h1>Hello World!</h1>


        <a href="javascript:addRow('table')">Add Row</a><a href="javascript:removeRow('table')" >Remove</a>
        <table id="table" border='1'>


        </table>

    </body>
</html>

现在这可能不是您正在寻找的。但是根据你提出的问题以及你提供的信息，这是我能给出的最佳建议。

MongoDB嵌套查询 - BadValue错误

1 个答案: