避免使用Lambdaj进行循环

Question

如何使用lambdaj避免这个循环，我想将List角色中的所有元素添加到另一个列表中

Firefox

我使用Java 7所以，Java 8 lambda表达式无法工作，我需要一个解决方案Lambdaj library

Answer 1

使用java 8：

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>




  <tr class='skip'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='skip'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='skip'>
    <td>First</td>
    <td>Second</td>
  </tr>

  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>
  <tr class='include'>
    <td>First</td>
    <td>Second</td>
  </tr>

</table>

如果lista已经包含数据：

String tipo = "type_1";
lista = personas.stream()
             .map(person -> new SimpleResultForm(tipo, person))
             .collect(Collectors.toList());

Answer 2

在Java 8中，假设您已经创建了列表“lista”，那么这个单行应该可以完成工作。

String tipo = "type_1";
personas.stream().forEach(e -> lista.add(new SimpleResultForm(tipo, e)));