计算具有相同月份的行数

Question

我是StackOverflow的新手，所以我为格式错误道歉。

注意：我正在使用Oracle SQL Developer。

我正在尝试转换以下查询结果：

这样的事情：

目前我在主SQL中的工作原理，但它正在使用如下的子查询：

SELECT distinct(eprdgrp.name)   product_group,
   eprodpkg.name            product_name,
(select count(creation_date) from ECPS_CA 
   where EXTRACT(month from CREATION_DATE)='2'
 AND STATUS='STATUS_NAME'
 AND ABC_CA.ID=ABC_CA.MASTER_ID  
   AND ABC_CA.PROD_PKG_ID IN (SELECT ID FROM ABC_PROD_PKG WHERE NAME=eprodpkg.name))     submission_feb,
   (select count(creation_date) from ABC_CA 
   where EXTRACT(year from CREATION_DATE)=(2016) 
   and EXTRACT(month from CREATION_DATE)='3' 
   AND STATUS='STATUS_NAME'
 AND ABC_CA.ID=ABC_CA.MASTER_ID       
 AND ABC_CA.PROD_PKG_ID IN (SELECT ID FROM ABC_PROD_PKG WHERE NAME=eprodpkg.name))     submission_mar,
...

我尝试使用此代码：

(select count(eca.creation_date) from dual
   where EXTRACT(month from eca.CREATION_DATE)='2'   
  )     submission_feb,
   (select count(eca.creation_date) from dual
   where EXTRACT(month from eca.CREATION_DATE)='3'   
  )     submission_mar,

但它会产生不同的结果

似乎1和0只是指示是否存在product_group，product_name和month组合的结果。

感谢任何帮助，我希望我解释得很好！

提前致谢！

Answer 1

试试这个

select 
prod_name, name, 
sum(Case when month(creation_date)=2 then 1 else 0 end) as submission_feb,
sum(Case when month(creation_date)=3 then 1 else 0 end) as submission_mar
from ECPS_CA 
group by prod_name, name

Answer 2

我会这样做：

select a.product_group, a.product_name, sum(a.submission_feb) as 
submission_feb, sum(a.submission_mar) as submission_mar
from (
Select product_group, product_name, count(*) as submission_feb, 0 as   
submission_mar
from ECPS_CA
where EXTRACT(month from CREATION_DATE)='2'
group by product_group, product_name
union all
Select product_group, product_name, 0, count(*)
from ECPS_CA
where EXTRACT(month from CREATION_DATE)='3'
group by product_group, product_name
) a
group by a.product_group, a.product_name

Answer 3

您可以使用Oracle中的PIVOT函数：

SELECT * 
FROM 
    (SELECT prod_group, prod_NAME, EXTRACT(MONTH FROM creation_date) AS creation_month  
    FROM ECPS_CA) 
PIVOT (
    COUNT(*) FOR creation_month IN (
        1 AS SUBMISSION_JAN, 
        2 AS SUBMISSION_FEB, 
        3 AS SUBMISSION_MAR, 
        ... 
        12 AS SUBMISSION_DEC
        )
);