Question

解决

SELECT TO_DATE(PRODUCT_FINISH_DATE) - TO_DATE(PRODUCT_START_DATE)
FROM MANUFACTURED_PRODUCT
WHERE ROWNUM = 1
ORDER BY PRODUCT_START_DATE ASC;

-

表：MANUFACTURED_PRODUCT

列：PRODUCT_ID, PRODUCT_START_DATE, PRODUCT_FINISH_DATE

SS：http://i.imgur.com/L7BePwc.png

尝试1：

SELECT DATEDIFF(D, PRODUCT_START_DATE, PRODUCT_FINISH_DATE) as Difference
FROM MANUFACTURED_PRODUCT
ORDER BY PRODUCT_START_DATE ASC LIMIT 1;

错误1：

ORA-00933: SQL command not properly ended
00933. 00000 -  "SQL command not properly ended"
*Cause:    
*Action:
Error at Line: 3 Column: 32

尝试2：

SELECT DATEDIFF(D, PRODUCT_START_DATE, PRODUCT_FINISH_DATE) as Difference
FROM MANUFACTURED_PRODUCT
ORDER BY PRODUCT_START_DATE ASC;

错误2：

ORA-00904: "DATEDIFF": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 1 Column: 7

我看到的所有例子都是这样的：

select DATEDIFF(d, @start, @end)
from table
order by @start asc limit 1;

Answer 1

我认为应该是

select datediff(PRODUCT_START_DATE,PRODUCT_FINISH_DATE) as Difference from FROM MANUFACTURED_PRODUCT
ORDER BY PRODUCT_START_DATE ASC;

Answer 2

虽然您已将问题标记为mysql个问题，但您正在针对不支持oracle和LIMIT的{{1}}数据库运行查询。

您的第一个错误是因为您使用无法识别的DateDiff结束了查询，而第二个错误是因为未知函数LIMIT。

编辑：你可以使用这段代码：

DateDiff

Answer 3

试试这个

SELECT TO_DATE（PRODUCT_FINISH_DATE，＆＃39; dd / mm / yyyy＆＃39;） - TO_DATE（PRODUCT_START_DATE，＆＃39; dd / mm / yyyy＆＃39;）DAYS FROM MANUFACTURED_PRODUCT WHERE ROWNUM = 1 按产品订购_START_DATE;

SQL - 选择产品与最新开始日期之间的天数

3 个答案: