此语句用于我的应用
$result = query("SELECT p.IdPhoto, p.device_token, p.IdUser FROM photos p JOIN login l ON (l.IdUser = p.IdUser) WHERE p.IdPhoto='%d'", $IdPhoto);
我还想存储device_token值，所以我添加了这一行。
$result = query("SELECT p.IdPhoto, p.device_token, p.IdUser FROM photos p JOIN login l ON (l.IdUser = p.IdUser) WHERE p.IdPhoto='%d' AND p.device_token='%d' ", $IdPhoto, $token);
我在应用程序中运行这行代码并且在调用此行时会退出，这很奇怪，因为第一行有关如何将device_token值存储在变量和IdPhoto中的任何想法？
php_error.log
[05-Apr-2016 06:21:19 Europe/Berlin] PHP Warning: Missing argument 2 for stream(), called in /Applications/MAMP/htdocs/Hi2/index.php on line 44 and defined in /Applications/MAMP/htdocs/Hi2/api.php on line 123
[05-Apr-2016 06:21:19 Europe/Berlin] PHP Notice: Undefined variable: token in /Applications/MAMP/htdocs/Hi2/api.php on line 145
[05-Apr-2016 06:21:19 Europe/Berlin] PHP Notice: Undefined index: error in /Applications/MAMP/htdocs/Hi2/api.php on line 149
它说令牌是一个未定义的变量，这是我在方法中定义它的方式。
function stream($IdPhoto=0, $token)
{
if ($IdPhoto==0) {
...
} else {
$result = query("SELECT p.IdPhoto, p.device_token, p.IdUser FROM photos p JOIN login l ON (l.IdUser = p.IdUser) WHERE p.IdPhoto='%d' AND p.device_token='%d' ", $IdPhoto, $token);
}
声明$token变量的正确方法是什么？