Question

我有一个mysql存储过程，如果它能够成功执行两个更新并且插入并回滚所有内容，则返回1，如果不能，则返回0。这是它的样子：

CREATE DEFINER=`barrence`@`%` PROCEDURE `completed_procedure`(IN insubmissionid INT, OUT success INT)
BEGIN

DECLARE inbountyid INT;
DECLARE EXIT HANDLER FOR SQLEXCEPTION ROLLBACK;
DECLARE EXIT HANDLER FOR SQLWARNING ROLLBACK;

START TRANSACTION;

SET success = 0;
SET @inbountyid = (SELECT idbounty FROM submission WHERE idsubmission = insubmissionid);

UPDATE submission SET status='a' WHERE idsubmission = insubmissionid;

IF (SELECT ROW_COUNT() = 1)
THEN UPDATE bounty SET iscomplete=1 WHERE idbounty = @inbountyid;
END IF;

IF (SELECT ROW_COUNT() = 1)
THEN INSERT INTO completion (idperson, idbounty, datecompleted, idsubmission, mediaid, description,
    privatestatus, contenttype, totalamount)  
SELECT s.idperson, s.idbounty, s.datesubmitted, s.idsubmission,
    COALESCE(s.youtubeid, s.contentid) AS mediaidid, b.description, b.privatestatus,
    b.contenttype, COALESCE(SUM(amount),0) AS totalamount 
FROM submission s 
INNER JOIN bounty b on s.idbounty = b.idbounty 
INNER JOIN contribution c on s.idbounty = c.idbounty 
WHERE s.idsubmission = insubmissionid AND c.ispaid = 1;
END IF;

IF (SELECT ROW_COUNT() = 1)
THEN SET success = 1;
END IF;

IF (success = 0)
THEN ROLLBACK;
END IF;

SELECT success;

COMMIT;
END

当我在MySQL Workbench中调用此存储过程时，它似乎正常工作，执行所有更新/插入并返回1或0否则。但是，当我在我的node.js服务器和console.log上调用此存储过程时，它只返回成功变量，如果它是1但是如果为0则不返回它。这是我如何调用它：

db.acceptSubmission(submissionId, function(result) {
        console.log(result);
}

exports.acceptSubmission = function(submissionId, callback) {
    var sql = "CALL completed_procedure(?, @success)";
    var inserts = [submissionId];
    sql = mysql.format(sql, inserts);

    console.log("Running Admin Accept Submission Procedure: " + sql);

    dbcommon.executeStatement(pool, sql, callback);
};

成功时结果如下：

[ [ { success: 1 } ],
  { fieldCount: 0,
    affectedRows: 0,
    insertId: 0,
    serverStatus: 2,
    warningCount: 0,
    message: '',
    protocol41: true,
    changedRows: 0 } ]

这不是：

{ fieldCount: 0,
  affectedRows: 0,
  insertId: 0,
  serverStatus: 2,
  warningCount: 0,
  message: '',
  protocol41: true,
  changedRows: 0 }

我完全被难过了。发生了什么事？

Answer 1

我相信这就是你在使用的mysql模块在该上下文中看到结果时的行为方式。我相信，既然您知道如何解释响应，那么在这种情况下这是一个非问题，并且当您返回非零响应时，您将得到预期的结果。

存储过程有时在node.js中不返回值

1 个答案: