停止图标重复

Question

我正在制作一个JTable，它会覆盖将图标放入所需的表格中。这就是我所做的。但结果在所有单元格中打印图标不仅仅是我的第一个单元格而且不是我想要的。结果如下：

import random 
from __future_ import print_function

HANGMANPICS = ['''

 +---+
 |   |
     |
     |
     |
     |
     |
====== ''' , '''

 +---+
 |   |
 0   |
     |
     |
     |
     |
====== ''' , '''

 +---+
 |   |
 0   |
 |   |
     |
     |
     |
====== ''' , '''

  +---+
  |   |
  0   |
 /|   |
      |
      |
      |
======= ''' , '''

  +----+
  |    |
  0    |
 /|\   |
       |
       |
       |
======== ''' , '''
 +----+
  |    |
  0    |
 /|\   |
 /     |
       |
       |
======== ''' , '''

 +------+
  |     |
  0     |
 /|\    |
 / \    |
        |
        |
========= ''']

words = """ cougar badger beaver cobra lion tiger skin ventriloquist magician monkey moose pigeon 
rabbit rhino trout wombat kangaroo python lizard raven skunk peacock hoki crab prawns cancer 
sloth snake spider parrot penguin ferret eagle cock hen peahen turkey turtle dinosaur metaphor 
iteration object apple """.split()

def getRandomWord(wordList):
#this function returns a random string from the words list
    wordIndex = random.randint(0,len(wordList)-1) #as we count from 0
    return wordList[wordIndex]

def displayBoard(HANGMANPICS , missedLetters, correctLetters, secretWord):
    print (HANGMANPICS[len(missedLetters)])
    print() #give space after every string character

    print ('Missed letters: ', end = ' ')
    for letter in missedLetters:
        print (letter, end = ' ')
    print()

    blanks = '_' * len(secretWord)
    #replace blanks with correct guesses
    for i in range (len(secretWord)): 
        if secretWord[i] in correctLetters:
            blanks = blanks[:i] + secretWord[i] + blanks[i+1:]
    #show secret word with spaces between each letter
    for letter in blanks:
        print (letter , end=' ')
    print()


def getGuess(alreadyGuessed): #makes sure player enters a letter and nothing else
    while True:
        print ('Guess a letter.')
        guess = raw_input()
        guess = guess.lower()
        if len(guess) != 1:
            print "please enter a single character."
        elif guess in alreadyGuessed:
            print "you have already guessed that letter. Choose another."
        elif guess not in 'abcdefghijklmnopqrstuvwxyz':
           print "please only enter a letter"
        else:
            return guess #returns user i/p
#function is true if player wants to play again , else false
def playAgain():
    print "do you wanna play again? (yes or no)"
    return raw_input.lower().startswith('y')


print "<<<<<<<<<<< H A N G M A N >>>>>>>>>>>>"
missedLetters = ''
correctLetters = ''
secretWord = getRandomWord(words)
gameIsDone = False 

while True:
    displayBoard(HANGMANPICS , missedLetters , correctLetters , secretWord)
    #getting a letter from user
    guess = getGuess(missedLetters + correctLetters)

    if guess in secretWord:
        correctLetters = correctLetters + guess 

    #check if the player has won
    foundAllLetters = True 
    for i in range(len(secretWord)):
        if secretWord[i] not in correctLetters:
            foundAllLetters = False
            break 

    if foundAllLetters:
        print "Yes! the secret word is "   + secretWord + "! You win!"
        gameisDone = True 
    else:
        missedLetters = missedLetters + guess 

#check if player has exhausted his guess limits and lost 

    if len(missedLetters) == len(HANGMANPICS) - 1:
        displayBoard(HANGMANPICS , missedLetters , correctLetters , secretWord)
        print " you have run out of guesses! \n After " + str(len(missedLetters)) + "missed guesses and" + str(len(correctLetters)) 
        + "correct guesses  the word was  " + secretWord  
        gameisDone = True 

    if gameisDone:
        if playAgain():
            missedLetters = ''
            correctLetters = ''
            gameisDone = False   
            secretWord = getRandomWord(words)
        else:
            break  

Answer 1

将label.setIcon(null);添加到else块，否则您只需返回上次设置的内容

有关详细信息，请参阅Concepts: Editors and Renderers