用新值重建PHP重复对象数组

Question

经过太多时间对我期望的直接任务进行故障排除后，我相信我或者错过了一个明显的缺陷，或者构建了一个错误的心智模型，告诉我们应该如何运作。

我的实际数据要复杂得多，但我已将其简化为此示例。

我们说我有一个$my_array个对象：

$object1 = new stdClass();
    $object1->valueA = 'abc';
    $object1->valueB = 'def';
    $object1->valueC = '20160410';
$object2 = new stdClass();
    $object2->valueA = '123';
    $object2->valueB = '456';
    $object2->valueC = '20160408';
$object3 = new stdClass();
    $object3->valueA = 'foo';
    $object3->valueB = 'bar';
    $object3->valueC = '20160412';

$my_array = array(
    'X' => $object1,
    'Y' => $object2,
    'Z' => $object3
);

我想浏览每个对象，使用其中一个值来计算新属性，然后使用新的计算值将对象分配给新数组。

我是这样做的：

$new_array= array();
foreach($my_array as $key=>$obj){
    for($i=0;$i<=2;$i++){  //the real use case uses a slightly different loop, this is simpler/shorter for an example 
        $date = $obj->valueC + $i;  //use valueC and the loop to calculate a new value
        $obj->date = $date;  //add my new value to the object
        $new_array[$date][$key] = $obj;  //construct new array of arrays of objects. bits on bits on bytes.
    }
}

如果我将结果数组记录到Console，它看起来像这样：

[04-Apr-2016 22:09:28 UTC] Array
(
    [20160410] => Array
        (
            [X] => stdClass Object
                (
                    [valueA] => abc
                    [valueB] => def
                    [valueC] => 20160410
                    [date] => 20160412
                )

            [Y] => stdClass Object
                (
                    [valueA] => 123
                    [valueB] => 456
                    [valueC] => 20160408
                    [date] => 20160410
                )

        )

    [20160411] => Array
        (
            [X] => stdClass Object
                (
                    [valueA] => abc
                    [valueB] => def
                    [valueC] => 20160410
                    [date] => 20160412
                )

        )

    [20160412] => Array
        (
            [X] => stdClass Object
                (
                    [valueA] => abc
                    [valueB] => def
                    [valueC] => 20160410
                    [date] => 20160412
                )

            [Z] => stdClass Object
                (
                    [valueA] => foo
                    [valueB] => bar
                    [valueC] => 20160412
                    [date] => 20160414
                )

        )

    [20160408] => Array
        (
            [Y] => stdClass Object
                (
                    [valueA] => 123
                    [valueB] => 456
                    [valueC] => 20160408
                    [date] => 20160410
                )

        )

    [20160409] => Array
        (
            [Y] => stdClass Object
                (
                    [valueA] => 123
                    [valueB] => 456
                    [valueC] => 20160408
                    [date] => 20160410
                )

        )

    [20160413] => Array
        (
            [Z] => stdClass Object
                (
                    [valueA] => foo
                    [valueB] => bar
                    [valueC] => 20160412
                    [date] => 20160414
                )

        )

    [20160414] => Array
        (
            [Z] => stdClass Object
                (
                    [valueA] => foo
                    [valueB] => bar
                    [valueC] => 20160412
                    [date] => 20160414
                )

        )

)

现在，我希望$ new_array [＆＃39; 20160410＆＃39;] [＆＃39; X＆＃39;] - ＆gt;日期为20160410。毕竟，在2行内，我说，＆＃34;使用此值作为顶级数组键，并将其作为对象中的值＆＃34;。但无论我做什么，['X']的所有实例都具有相同的date值。 ['Y']和['Z']相同。

我的目标是能够将新计算的date值存储在对象中，同时还将该值用作分组键。

Answer 1

默认情况下，对象通过引用分配，因为您可以在manual：

中读取它

  

经常提到的PHP 5 OOP的一个关键点是“对象默认通过引用传递”。

所以你可以想象你在for循环中的作业：

$new_array[$date][$key] = $obj;

像这样：

$new_array[$date][$key] = &$obj;
                          ↑

这意味着您将在for循环的每次迭代中更新所有对象。要解决这个问题只需clone对象，例如

$new_array[$date][$key] = clone $obj;