给定一个JavaScript对象,如何将其转换为对象数组(每个对象都有键值)?
示例:
var data = { firstName: 'John', lastName: 'Doe', email: 'john.doe@gmail.com' }
结果如:
[
{ key: 'firstName', value: 'John' },
{ key: 'lastName', value: 'Doe' },
{ key: 'email', value: 'john.doe@gmail.com' }
]
答案 0 :(得分:40)
var data = { firstName: 'John', lastName: 'Doe', email: 'john.doe@gmail.com' }
var output = Object.entries(data).map(([key, value]) => ({key,value}));
console.log(output);
灵感来自post
答案 1 :(得分:13)
使用map
功能
var data = { firstName: 'John', lastName: 'Doe', email: 'john.doe@gmail.com' };
var result = Object.keys(data).map(key => ({ key, value: data[key] }));
console.log(result);
答案 2 :(得分:10)
您可以迭代对象的属性并为每个属性创建一个新对象。
var data = { firstName: 'John', lastName: 'Doe', email: 'john.doe@gmail.com' };
var result = [];
for(var key in data)
{
if(data.hasOwnProperty(key))
{
result.push({
key: key,
value: data[key]
});
}
}
答案 3 :(得分:5)
之前的回答让我觉得有更好的方法......
apf <- approxfun( x=sort(bdat$time), y=seq(length( bdat$time)) ,rule=2)
apf( adat$time)
#[1] 1.000 3.750 3.875
round( apf( adat$time))
#[1] 1 4 4
或在ES6中使用箭头功能:
Object.keys(data).map(function(key) {
return { key, value: data[key] };
});
答案 4 :(得分:5)
让您的生活更轻松,并将es6语法与地图一起使用
var output = Object.keys(data).map(key => {
return {
key: key,
value: data[key]
};
})
答案 5 :(得分:3)
var result = [];
for(var k in data) result.push({key:k,value:data[k]});
答案 6 :(得分:1)
执行此操作的一种替代方法,该方法适用于多级对象,并且不使用递归。
var output = []
var o = {
x:0,
y:1,
z:{
x0:{
x1:4,
y1:5,
z1:6
},
y0:2,
z0:[0,1,2],
}
}
var defer = [ [ o ,[ '_root_' ] ] ]
var _defer = []
while(defer.length){
var current = defer.pop()
var root = current[1]
current = current[0]
for(var key in current ){
var path = root.slice()
path.push(key)
switch( current[key].toString() ){
case '[object Object]':
_defer.push( [ current[key] , path ] )
break;;
default:
output.push({
path : path ,
value : current[key]
})
break;;
}
}
if(!defer.length)
defer = _defer.splice(0,_defer.length)
}
[
{ path: [ '_root_', 'x' ], value: 0 },
{ path: [ '_root_', 'y' ], value: 1 },
{ path: [ '_root_', 'z', 'y0' ], value: 2 },
{ path: [ '_root_', 'z', 'z0' ], value: [ 0, 1, 2 ] },
{ path: [ '_root_', 'z', 'x0', 'x1' ], value: 4 },
{ path: [ '_root_', 'z', 'x0', 'y1' ], value: 5 },
{ path: [ '_root_', 'z', 'x0', 'z1' ], value: 6 }
]
答案 7 :(得分:0)
或狂野地使key
和value
键可自定义:
module.exports = function objectToKeyValueArray(obj, keyName = 'key', valueName = 'value') {
return Object
.keys(obj)
.filter(key => Object.hasOwnProperty.call(obj, key))
.map(key => {
const keyValue = {};
keyValue[keyName] = key;
keyValue[valueName] = obj[key];
return keyValue;
});
};
答案 8 :(得分:0)
我会说要使用npm package flat。 对于嵌套对象和数组,效果惊人。
var flatten = require('flat')
flatten({
key1: {
keyA: 'valueI'
},
key2: {
keyB: 'valueII'
},
key3: { a: { b: { c: 2 } } }
})
// {
// 'key1.keyA': 'valueI',
// 'key2.keyB': 'valueII',
// 'key3.a.b.c': 2
// }
答案 9 :(得分:-2)
const array = [
{ key: "key1", value: "value1" },
{ key: "key2", value: "value2" },
];
const obj = Object.fromEntries(array.map(item => [item.key, item.value]));
console.log(obj);