Question

I have a table of records. The user is allowed to enter data based on the date the event happened. The table becomes something like this:

ID  Date        Name      Hrs
1   2016-03-01  Username   8    
2   2016-03-02  Username   8    
3   2016-03-03  Username   9    
4   2016-03-04  Username   10       
…               
31  2016-03-31  Username   8

I want to be able to display date (even without records) that the user didn't enter.

I also want to display all the records in the table breaking them into weeks. Something like this:

Day Date Name Hrs

Mon 2016-03-01  Username   8    
Tue 2016-03-02  Username   8    
Wed 2016-03-03  Username   9    
Thu 2016-03-04  Username   10   
Fri 2016-03-05  Username   10
Sat 2016-03-06  -
Sun 2016-03-07  Username   10

Mon 2016-03-08  Username   8    
Tue 2016-03-09  -
Wed 2016-03-10  -   
Thu 2016-03-11  -   
Fri 2016-03-12  Username   10
Sat 2016-03-13  -
Sun 2016-03-15  Username   10

...
...
...

Mon 2016-03-30  Username   8    
Tue 2016-03-31  Username   8

Below is my code:

<?php

...Connection to DB...

$query="SELECT *
        FROM  Table_I
        ORDER BY DATEPART(wk,date) as wk
       ";

$params = array($_REQUEST['query']);
$results = sqlsrv_query($conn, $query, array(), array( "Scrollable" => 'static' ));

if($results===false)
 { die( FormatErrors( sqlsrv_errors() ) ); }

$rows = sqlsrv_num_rows($results);
$array = array();

while ($row = sqlsrv_fetch_array($results, SQLSRV_FETCH_ASSOC)) 
    { 
      $array[] = $row;

    }
?>

<html>
<head></head>
<body>

<table border="1">

<?php

        for($a=0; $a<$rows; $a++)
        {       
        echo '<tr><td>'.$array[$a]['wk'].'</td>';
        echo '<td>'.date("l", strtotime($array[$a]['date'])).'</td>';
        echo '<td>'.date('d M Y', strtotime(strip_tags($array[$a]['date']))). "</td>";
        echo '<td>'.strip_tags($array[$a]['name'])."</td>";
        echo '<td>'.strip_tags($array[$a]['hrs'])."</td>";

        }

</body>
</html>

It prints alright but doesn't include dates the user didn't enter and doesn't break it down into each week. I'm very new to programming but it's fun though.

Please, help is greatly appreciated.

Answer 1

您可以从以下查询开始。我相信你可以通过一些微小的改变得到你想要的东西。

以下查询可为您提供缺少日期的信息。

;WITH numbers AS 
( 
 SELECT cast('2016-03-01' as date) AS num
 UNION ALL 
 SELECT dateadd(day, 1, num)
   FROM numbers  
     WHERE num < '2016-03-31'
) 
select num as MissingDate
from numbers
  left join yourEventTable on yourEventTable.Dt = numbers.num
where ID is null

使用上述查询，您可以按周编号分组：

;WITH numbers AS 
( 
 SELECT cast('2016-03-01' as date) AS num 
 UNION ALL 
 SELECT dateadd(day, 1, num) FROM numbers  
     WHERE num < '2016-03-31'
) 
, dys as (
select num 
from numbers
)
select datepart(week, num), *
from dys 
  left join #events on #events.Dt = dys.num

以下示例，

PHP MSSQL weekly event

1 个答案: