Question

这是我的数据库表：

    CREATE TABLE IF NOT EXISTS `inspection_report` (
    `Inspection_datetime` datetime NOT NULL,
    `Line` char(5) NOT NULL,
    `S` int(11) NOT NULL,
    `A` int(11) NOT NULL,
    `B` int(11) NOT NULL,
    `C` int(11) NOT NULL,
INSERT INTO `inspection_report` (`Inspection_datetime`,`Line`,`S`, `A`, `B`, `C`) VALUES
('2010-09-01 09:08:01','FA 05',0, 0, 0, 0),('2010-09-02 14:24:35','FA 07',0, 0, 1, 0),('2010-09-01 09:08:01','fa 05',0, 1, 1, 0),('2010-09-01 16:24:04','FA 03', 0, 1, 0, 0);

我有很多这个表的数据。如果我想显示结果，我该怎么做：

Line      1st week        2nd week      3rd week   4th week    5th week   total
   FA 03        20                32          10         12          35        109
   FA 05        12                 5          10         10          25         62
   FA 07         0                 0           1         1            0          2

一个月有很多数据。我希望将它们分开计算一周。如果有大约一周的数据，则脚本将自动计算它们并在第1周，第2周，第3周等分享它们。我怎么做？或者你有什么想法吗？如何使用YEARweek()命令？

Answer 1

你需要做这样的事情

SELECT
  n.name,
  w1.amount,
  w2.amount,
  ...
  IFNULL(w1.amount,0) + IFNULL(w2.amount,0) + .... AS total
FROM
   yourTable AS n
LEFT JOIN (
  SELECT name, SUM(qty) AS amount FROM yourTable WHERE DAY(date) BETWEEN 1 AND 7 GROUP BY name
) AS w1 USING (name)
LEFT JOIN (
  SELECT name, SUM(qty) AS amount FROM yourTable WHERE DAY(date) BETWEEN 8 AND 14 GROUP BY name
) AS w2 USING (name)
...

Answer 2

请看一下以下内容：

http://www.artfulsoftware.com/infotree/queries.php?bw=1280#78

索引页面在这里：

http://www.artfulsoftware.com/infotree/queries.php?bw=1280

示例数据透视查询：

SELECT 
  IFNULL(empId,'Totals') AS EmpId,
  sums.2005, sums.2006, sums.2007,
  sums.2005 + sums.2006 + sums.2007 AS Sums
FROM (
  SELECT
    EmpID,
    SUM(IF(Yr=2005,sales,0)) As '2005',
    SUM(IF(Yr=2006,sales,0)) As '2006',
    SUM(IF(Yr=2007,sales,0)) As '2007'
  FROM Sales
  GROUP BY EmpID WITH ROLLUP
) AS sums;
+--------+----------+----------+----------+-----------+
| EmpId  | 2005     | 2006     | 2007     | Sums      |
+--------+----------+----------+----------+-----------+
| 1      | 12000.00 | 18000.00 | 25000.00 |  55000.00 |
| 2      | 15000.00 |  6000.00 |     0.00 |  21000.00 |
| 3      |     0.00 | 20000.00 | 24000.00 |  44000.00 |
| Totals | 27000.00 | 44000.00 | 49000.00 | 120000.00 |
+--------+----------+----------+----------+-----------+

Answer 3

SELECT
  A.Line,
  week1.1stweek,
  week2.2ndweek,
  ...
  IFNULL(week1.1stweek,0) + IFNULL(week2.2ndweek,0) + .... AS total
FROM
   inspection_report AS A
LEFT JOIN (
  SELECT Line, (SUM(S) + SUM(A) + SUM(B)*0.4 + SUM(C)*0.1)/COUNT(Serial_number) AS 1stweek FROM inspection_report WHERE DAY(Inspection_datetime) BETWEEN 1 AND 7 GROUP BY Line, WEEK, YEAR) AS week1 USING (Line)
LEFT JOIN (
  SELECT Line, (SUM(S) + SUM(A) + SUM(B)*0.4 + SUM(C)*0.1)/COUNT(Serial_number) AS 2ndweek FROM inspection_report WHERE DAY(Inspection_datetime) BETWEEN 8 AND 14 GROUP BY Line, WEEK, YEAR) AS week2 USING (Line)
...
GROUP BY Line

Answer 4

您可以使用SQL Server的Pivot功能。请参阅以下示例。

CREATE TABLE MyData
(
    ItemDate DATETIME,
    ItemName VARCHAR(200),
    ItemQty  INT
)
GO

DECLARE @I INT 
SET @i = 1
WHILE @i < 1000
BEGIN
    INSERT INTO MyData VALUES(GETDATE()-@I, 'NAME ' + CONVERT(VARCHAR(5),@I % 5), RAND()*100)
    SET @I = @I + 1
END
GO

SELECT ItemName, [1] AS 'WEEK-1', [2] AS 'WEEK-2', [3] AS 'WEEK-3', [4] AS 'WEEK-4'
FROM (SELECT ItemName, DATEPART(wk, ItemDate) WeekNum, ItemQty 
        FROM MyData) AS SourceTable
PIVOT
(
    SUM(ItemQty)
    FOR WeekNum IN ([1], [2], [3], [4])
) AS PivotTable;

在mysql中按周计算数据和分组

4 个答案: