使用批处理命令

Question

我有10-20个目录，每个文件夹里面有很多文件。
我想在每个文件夹中的每个文件包中加入一个文件，所以如果我有20个带有2300个文件的文件夹，我想要20个加入的文件。

实施例

INPUT

folder1 - 500 files
folder2 - 340 files
folder3 - 5 files

OUTPUT REQUEST
folder1.txt (500 joined files)
folder2.txt (340 joined files)
folder3.txt (5 joined files)

但是我有很多文件夹，因此我尝试找到 .bat 命令来自动创建此操作。

视频：what i want

Answer 1

Assuming each of your files is text file with a newline terminator at the end of each final line, then you can use the following:

for %%F in ("folder1" "folder2" "folder3") do >"%%F.txt" type "%%~F\*"

The name of each file will be output to the screen via stderr.

If you want to hide the file names:

for %%F in ("folder1" "folder2" "folder3") do >"%%F.txt" 2>nul type "%%~F\*"

If you want the file names to be included in the text file output:

for %%F in ("folder1" "folder2" "folder3") do >"%%F.txt" 2>&1 type "%%~F\*"

IF you want to process all folders within your current directory, then change the FOR command for any of the commands listed above to look like:

for /D %%F in (*) do ...