我试图显示相应问题ID的相应评论,但所有评论都显示在每个帖子中。 实际上,qusetion ID的值不会到达它所假设的所需表和那个表
name: add_topic.php
<body>
<?php
$con=mysqli_connect('localhost','root','');
if(!$con)
{
die("could not connect to the server".mysqli_error());
}
mysqli_select_db($con,'forum');
// Get value of id that sent from hidden field
$id=$_POST['id'];
// Find highest answer number.
$q="SELECT MAX(a_id) AS Maxa_id FROM forum_ans WHERE que_id='$id'";
$result=mysqli_query($con,$q);
$row=mysqli_fetch_assoc($result);
// add + 1 to highest answer number and keep it in variable name "$Max_id". if there no answer yet set it = 1
if ($row) {
$Max_id = $row['Maxa_id']+1;
}
else {
$Max_id = 1;
}
// get values that sent from form
$a_name=$_POST['a_name'];
$a_email=$_POST['a_email'];
$a_ans=$_POST['a_ans'];
$datetime=date("d/m/y H:i:s"); // create date and time
// Insert answer
$q2="INSERT INTO forum_ans(que_id, a_id, a_name, a_email, a_ans, a_datetime)VALUES('$id', '$Max_id', '$a_name', '$a_email', '$a_ans', '$datetime')";
$result2=mysqli_query($con,$q2);
if($result2){
echo "Successful<BR>";
echo "<a href='view_topic.php?id=".$id."'>View your answer</a>";
// If added new answer, add value +1 in reply column
$q3="UPDATE forum_que SET reply='$Max_id' WHERE id='$id'";
$result3=mysqli_query($con,$q3);
}
else {
echo "ERROR";
}
// Close connection
mysqli_close($con);
?>
</body>
命名为que_id的块显示值0(因为我已将0设置为其默认值),这是它的主要原因但我无法解决此问题。请帮忙......
name: view_topic.php
<body>
<?php
$con=mysqli_connect('localhost','root','');
if(!$con)
{
die("could not connect to the server".mysqli_error());
}
mysqli_select_db($con,'forum');
// get value of id that sent from address bar
$id=$_GET['id'];
$q="SELECT * FROM forum_que WHERE id='$id'";
$result=mysqli_query($con,$q);
$row=mysqli_fetch_assoc($result);
?>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td><table width="100%" border="0" cellpadding="3" cellspacing="1" bordercolor="1" bgcolor="#FFFFFF">
<tr>
<td bgcolor="#F8F7F1"><strong><?php echo $row['topic']; ?></strong></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><?php echo $row['detail']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>By :</strong> <?php echo $row['name']; ?> <strong>Email : </strong><?php echo $row['email'];?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Date/time : </strong><?php echo $row['datetime']; ?></td>
</tr>
</table></td>
</tr>
</table>
<BR>
<?php
// Switch to table "forum_answer"
$q2="SELECT * FROM forum_ans WHERE que_id='$id'";
$result2=mysqli_query($con,$q2);
while($row2=mysqli_fetch_assoc($result2)){
?>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td><table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td bgcolor="#F8F7F1"><strong>ID</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><?php echo $row2['a_id']; ?></td>
</tr>
<tr>
<td width="18%" bgcolor="#F8F7F1"><strong>Name</strong></td>
<td width="5%" bgcolor="#F8F7F1">:</td>
<td width="77%" bgcolor="#F8F7F1"><?php echo $row2['a_name']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Email</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><?php echo $row2['a_email']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Answer</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><?php echo $row2['a_ans']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Date/Time</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><?php echo $row2['a_datetime']; ?></td>
</tr>
</table></td>
</tr>
</table><br>
<?php
}
$q3="SELECT view FROM forum_que WHERE id='$id'";
$result3=mysqli_query($con,$q3);
$row3=mysqli_fetch_assoc($result3);
$view=$row3['view'];
// if have no counter value set counter = 1
if(empty($view)){
$view=1;
$q4="INSERT INTO forum_que(view) VALUES('$view') WHERE id='$id'";
$result4=mysqli_query($con,$q4);
}
// count more value
$addview=$view+1;
$q5="update forum_que set view='$addview' WHERE id='$id'";
$result5=mysqli_query($con,$q5);
mysqli_close($con);
?>
<BR>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form name="form1" method="post" action="add_ans.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td width="18%"><strong>Name</strong></td>
<td width="3%">:</td>
<td width="79%"><input name="a_name" type="text" id="a_name" size="45"></td>
</tr>
<tr>
<td><strong>Email</strong></td>
<td>:</td>
<td><input name="a_email" type="text" id="a_email" size="45"></td>
</tr>
<tr>
<td valign="top"><strong>Answer</strong></td>
<td valign="top">:</td>
<td><textarea name="a_ans" cols="45" rows="3" id="a_ans"></textarea></td>
</tr>
<tr>
<td> </td>
<td><input name="id" type="hidden" value="<? echo $id; ?>"></td>
<td><input type="submit" name="Submit" value="Submit"> <input type="reset" name="Submit2" value="Reset"></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
</body>
name: add_topic.php
<body>
<?php
// get data that sent from form
$topic=$_REQUEST['topic'];
$detail=$_REQUEST['detail'];
$name=$_REQUEST['name'];
$email=$_REQUEST['email'];
$datetime=date("d/m/y h:i:s"); //create date time
$con=mysqli_connect('localhost','root','');
if(!$con)
{
die("could not connect to the server".mysqli_error());
}
mysqli_select_db($con,'forum');
$q="INSERT INTO`forum`.`forum_que`(topic, detail, name, email, datetime)VALUES('$topic', '$detail', '$name', '$email', '$datetime')";
if(mysqli_query($con,$q))
{
echo '<script>alert("Data Inserted Now redirecting to login page");</script>';
header('location:main_forum.php');
}
else
{
echo "error inserting record" . mysqli_error($con,$query);
echo '<script>alert("Error while inserting data");</script>';
}
mysqli_close($con);
?>
</body>
答案 0 :(得分:0)
如果有一个add_topic.php
,您有两个add_ans.php
我没有看到此代码存在任何确切问题您确定$id
在表单的隐藏字段中正确使用了吗?
可能会尝试在print_r($_POST);
页面上执行add_ans.php
,以查看表单实际传递的数据