所以这就是我的困境,我正在尝试搜索一个特定值的数组,但是我收到的错误是我不知道如何修复。这是我目前的代码:
import java.util.Arrays;
public class Marathon {
public static void main(String[] args) {
double[] weeks = {2,4.66,7.33,10,12.66,15.33,18,20.66,23.33,26};
double sum = 0;
int length = weeks.length;
for (double i : weeks)
sum += i;
System.out.println("What is the value for array element 2: " + weeks[1]);
System.out.println("What is the list length: " + length);
System.out.println("Sum of all miles run during the 10 week period: " + sum);
System.out.println("Does the list contain a week with 4 miles: ");
boolean retval = weeks.contains(4.00);
if (retval == true) {
System.out.println("10 is contained in the list");
}
else {
System.out.println("10 is not contained in the list");
}
}
}
我收到的错误消息如下:
Cannot invoke contains(double) on the array type double[]
Marathon.java/do while/src line 18 Java Problem
对此的任何帮助将不胜感激!提前谢谢。
答案 0 :(得分:1)
您可以使用Java 8执行此操作:
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它将您的double数组转换为DoubleStream。然后它将流与谓词相匹配,例如说我等于10.0。
我希望它有所帮助。
答案 1 :(得分:0)
你应该知道的是Java中的数组没有方法contains()。 你可以做的是循环数组并比较元素。