Question

我有两个字符串：

String s1 = "[143, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 157, 158, 159, 162, 163, 164]";

String s2 = "[20, 35, 74, 78, 124, 125, 126, 127, 131, 132, 143, 144, 145, 146]";

我想要做的就是找到这两个字符串中最小的公共数字。所以我先取代＆＃34; []＆＃34;符号，并将字符串中的数字提取为整数。然后使用循环查找最小公共数。程序如下：

s1 = s1.replace("[",""); 
s1 = s1.replace("]","");
String [] band = s1.split(",");     
s2 = s2.replace("[",""); 
s2 = s2.replace("]","");
String [] hotel = s1.split(",");    
System.out.println( EarliestCommonSlot(hotel,band) );

EarliestCommonSlot（）的定义如下：

public static int EarliestCommonSlot(String [] a1, String [] b1){
    int i=0,j=0;
    int common = -1;
    int [] a = new int [a1.length];
    int [] b = new int [b1.length];

    for(i = 0;i < a1.length;i++)
    {
        a[i] = Integer.parseInt( a1[i]);
        System.out.println(a1[i]);
    }
    for(i = 0;i < b1.length;i++)
    {
        b[i] = Integer.parseInt( b1[i]);
        System.out.println(b1[i]);
    }
    i = 0; j=0;
    while ( i< a.length && j < b.length){
        if ( a[i] == b[j] ){
            common = a[i]; break;
        }
        if ( a[i] < b[j] ){
            i++;
        }
        else j++;
    }
    return common;
}

但是当我运行该程序时，它有以下错误：

Exception in thread "main" java.lang.NumberFormatException: For input string: " 143"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:481)
    at java.lang.Integer.parseInt(Integer.java:527)
    at ClientReserve.EarliestCommonSlot(ClientReserve.java:39)
    at ClientReserve.main(ClientReserve.java:179)

为什么？我怎么能解决这个问题？

Answer 1

而不是

s1.replace("]"," "); // This replaces the bracket with a space.
                     // The number with the space will emit the error

使用：

s1.replace("]","");//This replaces the bracket with an empty string.

新代码：

s1 = s1.replace("[",""); 
s1 = s1.replace("]","");
String [] band = s1.split(", ");     
s2 = s2.replace("[",""); 
s2 = s2.replace("]","");
String [] hotel = s1.split(", ");    //Comma and a space. Thanks to SaviourSelf
System.out.println( EarliestCommonSlot(hotel,band) );

Answer 2

请从数组中的字符串中删除空格。这可以通过

来完成

st.replaceAll("\\s+","")和st.replaceAll("\\s","")

在错误本身中显示143在前缀中有空格。线程“main”中的异常java.lang.NumberFormatException：对于输入字符串：“143”

Answer 3

使用trim（）方法

String s1 = "[143, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 157, 158, 159, 162, 163, 164]";

    String s2 = "[20, 35, 74, 78, 124, 125, 126, 127, 131, 132, 143, 144, 145, 146]";
    s1 = s1.replace("[",""); 
    s1 = s1.replace("]","");
    String [] band = s1.split(",");     
    s2 = s2.replace("[",""); 
    s2 = s2.replace("]","");
    String [] hotel = s1.split(",");    
    System.out.println( EarliestCommonSlot(hotel,band) );



 public static int EarliestCommonSlot(String [] a1, String [] b1){
        int i=0,j=0;
        int common = -1;
        int [] a = new int [a1.length];
        int [] b = new int [b1.length];

        for(i = 0;i < a1.length;i++)
        {
            a[i] = Integer.parseInt( a1[i].trim());
            System.out.println(a1[i]);
        }
        for(i = 0;i < b1.length;i++)
        {
            b[i] = Integer.parseInt( b1[i].trim());
            System.out.println(b1[i]);
        }
        i = 0; j=0;
        while ( i< a.length && j < b.length){
            if ( a[i] == b[j] ){
                common = a[i]; break;
            }
            if ( a[i] < b[j] ){
                i++;
            }
            else j++;
        }
        return common;
    }

我已经运行了这个方法并且有效

Answer 4

public class Test {


  public static void main(String[] args) {



String s1 = "[143, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 157, 158, 159, 162, 163, 164]";

String s2 = "[20, 35, 74, 78, 124, 125, 126, 127, 131, 132, 143, 144, 145, 146]";
      s1 = s1.replace("[",""); 
      s1 = s1.replace("]","");
      s1 = s1.replace(" ","");
      String [] band = s1.split(",");     
      s2 = s2.replace("[",""); 
      s2 = s2.replace("]","");

      String [] hotel = s1.split(",");    
      System.out.println( EarliestCommonSlot(hotel,band) );
  }
  public static int EarliestCommonSlot(String [] a1, String [] b1){
        int i=0,j=0;
        int common = -1;
        int [] a = new int [a1.length];
        int [] b = new int [b1.length];

        for(i = 0;i < a1.length;i++)
        {
            a[i] = Integer.parseInt( a1[i]);
            System.out.println(a1[i]);
        }
        for(i = 0;i < b1.length;i++)
        {
            b[i] = Integer.parseInt( b1[i]);
            System.out.println(b1[i]);
        }
        i = 0; j=0;
        while ( i< a.length && j < b.length){
            if ( a[i] == b[j] ){
                common = a[i]; break;
            }
            if ( a[i] < b[j] ){
                i++;
            }
            else j++;
        }
        return common;
    }    
   }

如何使用＆＃34; []＆＃34;转换字符串成整数数组

4 个答案: