使用Espresso和Hamcrest,
如何计算recyclerView中可用的项目编号?
例子:我想检查特定的RecyclerView中是否有5个项目显示(必要时滚动)。
答案 0 :(得分:72)
这里有一个示例ViewAssertion来检查RecyclerView项目计数
public class RecyclerViewItemCountAssertion implements ViewAssertion {
private final int expectedCount;
public RecyclerViewItemCountAssertion(int expectedCount) {
this.expectedCount = expectedCount;
}
@Override
public void check(View view, NoMatchingViewException noViewFoundException) {
if (noViewFoundException != null) {
throw noViewFoundException;
}
RecyclerView recyclerView = (RecyclerView) view;
RecyclerView.Adapter adapter = recyclerView.getAdapter();
assertThat(adapter.getItemCount(), is(expectedCount));
}
}
然后使用此断言
onView(withId(R.id.recyclerView)).check(new RecyclerViewItemCountAssertion(5));
我已经开始编写一个库,可以使用espresso和uiautomator使测试变得更简单。这包括RecyclerView操作和断言的工具。 https://github.com/nenick/espresso-macchiato例如使用方法assertItemCountIs(int)参见EspRecyclerView
答案 1 :(得分:26)
向@Stephane's answer添加一些语法糖。
colorPrimary
用法:
public class RecyclerViewItemCountAssertion implements ViewAssertion {
private final Matcher<Integer> matcher;
public static RecyclerViewItemCountAssertion withItemCount(int expectedCount) {
return withItemCount(is(expectedCount));
}
public static RecyclerViewItemCountAssertion withItemCount(Matcher<Integer> matcher) {
return new RecyclerViewItemCountAssertion(matcher);
}
private RecyclerViewItemCountAssertion(Matcher<Integer> matcher) {
this.matcher = matcher;
}
@Override
public void check(View view, NoMatchingViewException noViewFoundException) {
if (noViewFoundException != null) {
throw noViewFoundException;
}
RecyclerView recyclerView = (RecyclerView) view;
RecyclerView.Adapter adapter = recyclerView.getAdapter();
assertThat(adapter.getItemCount(), matcher);
}
}
答案 2 :(得分:17)
要完成nenick的答案,并提供更灵活的解决方案,以测试项目cout是否更大,更少,但是...
public class RecyclerViewItemCountAssertion implements ViewAssertion {
private final Matcher<Integer> matcher;
public RecyclerViewItemCountAssertion(int expectedCount) {
this.matcher = is(expectedCount);
}
public RecyclerViewItemCountAssertion(Matcher<Integer> matcher) {
this.matcher = matcher;
}
@Override
public void check(View view, NoMatchingViewException noViewFoundException) {
if (noViewFoundException != null) {
throw noViewFoundException;
}
RecyclerView recyclerView = (RecyclerView) view;
RecyclerView.Adapter adapter = recyclerView.getAdapter();
assertThat(adapter.getItemCount(), matcher);
}
}
用法:
onView(withId(R.id.recyclerView)).check(new RecyclerViewItemCountAssertion(5));
onView(withId(R.id.recyclerView)).check(new RecyclerViewItemCountAssertion(greaterThan(5));
onView(withId(R.id.recyclerView)).check(new RecyclerViewItemCountAssertion(lessThan(5));
// ...
答案 3 :(得分:6)
基于@Sivakumar Kamichetty回答:
COUNT = 0;
COUNT
变量转移到一个元素数组。result
是不必要的。不好,但有效:
public static int getCountFromRecyclerView(@IdRes int RecyclerViewId) {
final int[] COUNT = {0};
Matcher matcher = new TypeSafeMatcher<View>() {
@Override
protected boolean matchesSafely(View item) {
COUNT[0] = ((RecyclerView) item).getAdapter().getItemCount();
return true;
}
@Override
public void describeTo(Description description) {}
};
onView(allOf(withId(RecyclerViewId),isDisplayed())).check(matches(matcher));
return COUNT[0];
}
答案 4 :(得分:5)
我使用以下方法获取RecyclerView的计数
public static int getCountFromRecyclerView(@IdRes int RecyclerViewId) {
int COUNT = 0;
Matcher matcher = new TypeSafeMatcher<View>() {
@Override
protected boolean matchesSafely(View item) {
COUNT = ((RecyclerView) item).getAdapter().getItemCount();
return true;
}
@Override
public void describeTo(Description description) {
}
};
onView(allOf(withId(RecyclerViewId),isDisplayed())).check(matches(matcher));
int result = COUNT;
COUNT = 0;
return result;
}
用法 -
int itemsCount = getCountFromRecyclerView(R.id.RecyclerViewId);
然后执行断言以检查itemsCount是否符合预期
答案 5 :(得分:1)
您可以创建自定义BoundedMatcher
:
object RecyclerViewMatchers {
@JvmStatic
fun hasItemCount(itemCount: Int): Matcher<View> {
return object : BoundedMatcher<View, RecyclerView>(
RecyclerView::class.java) {
override fun describeTo(description: Description) {
description.appendText("has $itemCount items")
}
override fun matchesSafely(view: RecyclerView): Boolean {
return view.adapter.itemCount == itemCount
}
}
}
}
然后像这样使用它:
onView(withId(R.id.recycler_view)).check(matches((hasItemCount(5))))
答案 6 :(得分:1)
有效的答案是可行的,但是我们只需一行就可以解决此问题,而无需了解适配器:
onView(withId(R.id.your_recycler_view_id)).check(matches(hasChildCount(2)))
用您的ID替换your_recycler_view_id
,用要声明的数字替换2
。