Question

这是我的所有PHP代码。

define('DB_SERVER', "mysql.com");
define('DB_USER', "");
define('DB_PASSWORD', "!");
define('DB_DATABASE', "");
$conn = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_DATABASE);
$query = "SELECT * FROM `accountsToDo` ORDER BY id LIMIT 1";
$result = $conn->query($query);
while($row = $result->fetch_assoc()) {
    $percentageOfMessages =($row["percentageOfMessages"]);  
    $RemoveDeletedAccounts =($row["RemoveDeletedAccounts"]);    
    $blacklistUsernames =($row["blacklistUsernames"]);  
    $userEmail =($row["userEmail"]);  
    $CUse =($row["CUse"]);  
    $CPa =($row["CPa"]);  
}
$conn->close();
?>
<ul> 
    <li id="percentageOfMessages"><?php echo $percentageOfMessages; ?></li>
    <li id="RemoveDeletedAccounts"><?php echo $RemoveDeletedAccounts; ?></li>
    <li id="blacklistUsernames"><?php echo $blacklistUsernames; ?></li>
    <li id="userEmail"><?php echo $userEmail; ?></li>
    <li id="CUse"><?php echo $CUse; ?></li>
    <li id="CPa"><?php echo $CPa; ?></li>
</ul>

我的问题是，在我获得该行的值之后。我想继续删除那一行。

    $CUse =($row["CUse"]);  
    $CPa =($row["CPa"]);  
}

$conn = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_DATABASE);
$query = "DELETE FROM `accountsToDo` WHERE 1 ORDER BY id LIMIT 1";
$conn->query($query);

$conn->close();
?>

但是当我把它放在那里时，我得到一个错误说......

在null
上调用成员函数close（）

如何解决此错误？

Answer 1

这应该是：

当你删除某些东西时。确保定义要删除的内容，否则它将删除所有/全部！请参阅下面的调整。

define('DB_SERVER', "mysql.com");
define('DB_USER', "");
define('DB_PASSWORD', "!");
define('DB_DATABASE', "");
$conn = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_DATABASE);
$query = "SELECT * FROM `accountsToDo` ORDER BY id LIMIT 1";
$result = $conn->query($query);
$row = $result->fetch_assoc();
?>
<ul> 
    <li id="percentageOfMessages"><?php echo $row["percentageOfMessages"]; ?></li>
    <li id="RemoveDeletedAccounts"><?php echo $row["RemoveDeletedAccounts"]; ?></li>
    <li id="blacklistUsernames"><?php echo $row["blacklistUsernames"]; ?></li>
    <li id="userEmail"><?php echo $row["userEmail"]; ?></li>
    <li id="CUse"><?php echo $row["CUse"]; ?></li>
    <li id="CPa"><?php echo $row["CPa"]; ?></li>
</ul>

$query = "DELETE FROM `accountsToDo` WHERE `id` = {$row['id']}";
$conn->query($query);

$conn->close();
?>

尝试执行第二个查询时出错

1 个答案: