Question

我真的很困惑，不熟悉Python，我正在开发一个脚本，用于在Python27上搜索产品的网站。我试图使用urllib2来执行此操作，当我运行脚本时，它会打印多个回溯错误。建议？

脚本：

import urllib2, zlib, json

url='https://launches.endclothing.com/api/products'
req = urllib2.Request(url)
req.add_header(':host','launches.endclothing.com');req.add_header(':method','GET');req.add_header(':path','/api/products');req.add_header(':scheme','https');req.add_header(':version','HTTP/1.1');req.add_header('accept','application/json, text/plain, */*');req.add_header('accept-encoding','gzip,deflate');req.add_header('accept-language','en-US,en;q=0.8');req.add_header('cache-control','max-age=0');req.add_header('cookie','__/');req.add_header('user-agent','Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Ubuntu Chromium/37.0.2062.120 Chrome/37.0.2062.120 Safari/537.36');
resp = urllib2.urlopen(req).read()
resp = zlib.decompress(bytes(bytearray(resp)),15+32)
data = json.loads(resp)
for product in data:
    for attrib in product.keys():
        print str(attrib)+' :: '+ str(product[attrib])
    print '\n'

错误（S）：

C:\Users\Luke>py C:\Users\Luke\Documents\EndBot2.py
Traceback (most recent call last):
  File "C:\Users\Luke\Documents\EndBot2.py", line 5, in <module>
    resp = urllib2.urlopen(req).read()
  File "C:\Python27\lib\urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "C:\Python27\lib\urllib2.py", line 391, in open
    response = self._open(req, data)
  File "C:\Python27\lib\urllib2.py", line 409, in _open
    '_open', req)
  File "C:\Python27\lib\urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "C:\Python27\lib\urllib2.py", line 1181, in https_open
    return self.do_open(httplib.HTTPSConnection, req)
  File "C:\Python27\lib\urllib2.py", line 1148, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 1] _ssl.c:499: error:14077438:SSL routines:SSL23_GET_SERVER_HELLO:tlsv1 alert internal error>

Answer 1

您遇到了SSL请求配置问题。对不起，但我无法更正您的代码，因为我们已经在2016年了，而且您应该使用一个很棒的图书馆：requests

所以它的用法非常简单：

>>> user_agent = 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:40.0) Gecko/20100101 Firefox/40.1'
>>> result = requests.get('https://launches.endclothing.com/api/products', headers={'user-agent': user_agent})
>>> result
<Response [200]>
>>> result.json()
[{u'name': u'Adidas Consortium x HighSnobiety Ultraboost', u'colour': u'Grey', u'id': 30, u'releaseDate': u'2016-04-09T00:01:00+0100', …

您会注意到我在上一个查询中更改了用户代理以使其正常工作，因为奇怪的是，该网站拒绝对requests的API访问：

>>> result = requests.get('https://launches.endclothing.com/api/products')
>>> result
<Response [403]>
>>> result.text
This website is using a security service to protect itself from online attacks. The action you just performed triggered the security solution. There are several actions that could trigger this block including submitting a certain word or phrase, a SQL command or malformed data.</p></div><div class="error-right"><h3>What can I do to resolve this?</h3><p>If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware.</p><p>If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices.

否则，既然您已经尝试requests并且您的生活发生了变化，您可能仍会再次遇到此问题。正如您可能从互联网上的许多地方读到的那样，这与SNI and outdated libraries有关，您可能会头疼，试图解决这个问题。我最好的建议是升级到Python3，因为问题很可能通过安装一个新的python版本的python和所涉及的库来解决。

HTH

使用urllib2的Python回溯错误

1 个答案: