Question

对C＃来说相当新鲜。我有以下代码来计算两点之间的距离和角度。但是，它不会显示小数点（需要小数点后三位。我认为浮点数据类型可以处理十进制数？

e.g。点1 x = 2，点1 y = 2，点2 x = 1，点2 y = 1。

距离计算为1，角度计算为-1。距离应为1.414＆amp;角度应该是-135.000度，所以如果它有意义的话就像它上下圆一样......

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace AngleDistanceCalc
{
    class Program
    {
        static void Main(string[] args)
        {
            // print welcome message
            Console.WriteLine("Welcome. This application will calculate the distance between two points and display the angle.");

            Console.WriteLine("Please enter point 1 X value:");
            float point1X = float.Parse(Console.ReadLine());

            Console.WriteLine("Please enter point 1 Y value:");
            float point1Y = float.Parse(Console.ReadLine());

            Console.WriteLine("Please enter point 2 X value:");
            float point2X = float.Parse(Console.ReadLine());

            Console.WriteLine("Please enter point 2 y value:");
            float point2Y = float.Parse(Console.ReadLine());

            float deltaX = point2X - point1X;
            float deltaY = point2Y - point2X;

            double distance = Math.Sqrt(deltaX * deltaX + deltaY * deltaY);

            Console.WriteLine("The distance between the points is: {0}", distance);

            Console.WriteLine("The angle between the points is: {0}",  deltaX);
        }
    }
}

Answer 1

float deltaY = point2Y - point2X;

您在上面的行中有一个错误。你需要计算：

float deltaY = point2Y - point1Y;

此外，您需要引入用于计算角度的逻辑。公式在this answer：

下讨论

var angle = Math.Atan2(deltaY, deltaX) * 180 / Math.PI;
Console.WriteLine("The angle between the points is: {0}", angle);

C＃中的小数点

1 个答案: