Question

警告：mysqli_connect（）期望参数2是字符串，对象在第56行第56行的C：\ wamp \ www \ social \ includes \ acceso.php中给出：

mysqli_connect($database_conexionredsocial, $conexionredsocial);

警告：mysqli_query（）期望参数1为mysqli，给定字符串在第61行第61行的C：\ wamp \ www \ ksocial \ includes \ acceso.php

$LoginRS = mysqli_query($LoginRS__query, $conexionredsocial) or die(mysql_error());

我需要帮助。如果有人带来解决方案，我将非常感激。

Answer 1

在corresponding manual page上可以看到，mysqli_query()函数接受字符串参数。在发送对象时。

很可能你有一个多余的mysqli_connect调用，发送一个现有的连接。所以，摆脱

mysqli_connect($database_conexionredsocial, $conexionredsocial);

Answer 2

你需要传递3个参数，解决方法是：

查询语法为：

mysqli_query(connection,query,resultmode);

PHP

$LoginRS = mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

// Perform queries 
mysqli_query($LoginRS,"SELECT * FROM Persons");
mysqli_query($LoginRS,"INSERT INTO Persons (FirstName,LastName,Age) 
VALUES ('Glenn','Quagmire',33)");

mysqli_close($LoginRS);

Answer 3

Create a PHP file with your connection variables:

<?php
$DBHost = "host";
$DBUser = "user";
$DBPass = "pass";
change your connection file to this:

<?php
require("connectionsettings.php");
$connection = mysqli_connect($DBHost, $DBUser, $DBPass);
if (!$connection) {
    die('Connect Error: ' . mysqli_connect_error());
}

mysqli_connect（）期望参数2为字符串

3 个答案: