Question

感谢有人可以帮我解决这个问题。请参阅我的图片以进一步了解。
https://onedrive.live.com/redir?resid=F95DD828CA2E63D7!1326&authkey=!AEbavlKl38fBJYI&v=3&ithint=photo%2cjpg

我有一个实际的CasperJS html捕获截图。它显示casperjs正确进入谷歌领域。问题是

CasperJS没有调用我的函数getLinks＆gt;＆gt; links = this.evaluate（getLinks）;. ＆GT;＆GT;它返回null。
我测试了实际的选择器＆gt;＆gt; querySelectorAll（'h3.r a'），它在浏览器中工作。

var casper = require（'casper'）。create（{ 详细说明：是的， logLevel：'debug'， pageSettings：{ userAgent：'Mozilla / 5.0（Windows NT 6.1）AppleWebKit / 537.36（KHTML，如Gecko）Chrome / 41.0.2228.0 Safari / 537.36' } }）;

var url = 'http://www.google.com/';
var fs = require('fs');
var links = [];

function getLinks() {
    var links = document.querySelectorAll('h3.r a');
    this.echo('Getting links now-----------------------------------------')
    return Array.prototype.map.call(link, function(e) {
        return e.innerText;
    });
}

casper.start(url, function() {});

casper.then(function() {
    this.fillSelectors('form#tsf', {
        'input[name="q"]': 'Funny Man'
    }, true);
    this.echo('\n Filling is complete...');
})

casper.then(function() {
    this.mouseEvent('click', 'input[name="btnK"]');
    this.echo('Mouse Event Done...');
    casper.capture('screenshot/google_search0.png');
});

casper.then(function() {
    this.mouseEvent('click','button[name="btnG"]' );
    this.echo('***************************************Done');
    casper.capture('screenshot/google_search1.png');
});

casper.waitFor(function check() {
    return this.evaluate(function() {
        return document.querySelectorAll('#resultStats').length >= 1;
    });
}, function then() {    // step to execute when check() is ok
    casper.capture('screenshot/google_search2.png');
    links = this.evaluate(getLinks);
    console.log('BOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOyeahhhhhhhh')
}, function timeout() { // step to execute if check has failed
    casper.capture('screenshot/google_search3.png');
    this.echo('search page load has failed. go see why********************');
});

casper.then(function() {
    this.echo('++++++++++++++++++++++++++++++++++++++++++++++++++');
    links = this.evaluate(getLinks);

});

casper.run(function() {
    this.echo('Capturing screenshot...');
    casper.capture('screenshot/google2.png');
    fs.write('outputs/google_results4.html', this.getHTML(), 'w');
    this.echo(links);
    casper.exit();
});

非常感谢。

Casperjs没有返回Google搜索链接标题但是屏幕截图＆amp;源代码测试工作

0 个答案: