显示GCM参数以及消息

时间:2016-04-03 12:18:57

标签: c# android google-cloud-messaging

我正在尝试使用C#推送GCM。我成功将消息发送到手机。但只是整个字符串连同参数出现在手机上,而不是'消息'仅参数。

即:对于我的消息字符串:" gcmAction = gcmActionFeedback,title =请提供反馈,消息=您的反馈请"
在电话通知中,我能够看到" gcmAction = gcmActionFeedback,title =请提供反馈,消息=您的反馈请"在哪里我应该看到"您的反馈请"只要。

标题也没有显示出来。而当我通过http://gcm-alert.appspot.com/发送相同的GCM消息时,一切似乎都很完美。

Plz plz帮助。这是代码

 
public string SendNotification2(string deviceId, string message)
        {
            string GoogleAppID = "AIza.......xkQk";
            var SENDER_ID = "6666666666";
            var value = message;
            WebRequest tRequest;
            tRequest = WebRequest.Create("https://android.googleapis.com/gcm/send");
            tRequest.Method = "post";
            tRequest.ContentType = " application/x-www-form-urlencoded;charset=UTF-8";
            tRequest.Headers.Add(string.Format("Authorization: key={0}", GoogleAppID));

        tRequest.Headers.Add(string.Format("Sender: id={0}", SENDER_ID));

        string postData = "collapse_key=score_update&time_to_live=108&delay_while_idle=1&data.message=" + value + "&data.time=" + 
        System.DateTime.Now.ToString() + "&registration_id=" + deviceId + "";
        Console.WriteLine(postData);
        Byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        tRequest.ContentLength = byteArray.Length;

        Stream dataStream = tRequest.GetRequestStream();
        dataStream.Write(byteArray, 0, byteArray.Length);
        dataStream.Close();

        WebResponse tResponse = tRequest.GetResponse();

        dataStream = tResponse.GetResponseStream();

        StreamReader tReader = new StreamReader(dataStream);

        String sResponseFromServer = tReader.ReadToEnd();

        tReader.Close();
        dataStream.Close();
        tResponse.Close();
        return sResponseFromServer;
    }

tRequest.Headers.Add(string.Format("Sender: id={0}", SENDER_ID)); string postData = "collapse_key=score_update&time_to_live=108&delay_while_idle=1&data.message=" + value + "&data.time=" + System.DateTime.Now.ToString() + "&registration_id=" + deviceId + ""; Console.WriteLine(postData); Byte[] byteArray = Encoding.UTF8.GetBytes(postData); tRequest.ContentLength = byteArray.Length; Stream dataStream = tRequest.GetRequestStream(); dataStream.Write(byteArray, 0, byteArray.Length); dataStream.Close(); WebResponse tResponse = tRequest.GetResponse(); dataStream = tResponse.GetResponseStream(); StreamReader tReader = new StreamReader(dataStream); String sResponseFromServer = tReader.ReadToEnd(); tReader.Close(); dataStream.Close(); tResponse.Close(); return sResponseFromServer; }

1 个答案:

答案 0 :(得分:1)

您不能将所有字段都放入一个简单的消息字符串中。如果消息是字符串,android将完全按原样显示字符串。

因此,而不是...data.message=" + value +...将您的值分成您想要的不同字段(gcmAction,title,...),并将它们相应地添加到网址

string msg = "foo", title="bar", gcmAction="bla";
string postdata = "....&data.message="+msg+"&data.title="+title+"&data.gcmAction="+gcmAction +"&..."

我不知道所需和/或支持的字段的确切名称,您可能需要在文档中查找它们。

或者作为替代方法:您可以创建一个具有相应有效负载的JSON对象,并在正文中传输此playload,如this blog

所示