我有一个程序从命令行接收用户的输入。令人讨厌的是,当我第一次使用扫描仪时,输入的文本会在下一行(System.out.println
之后)进行。但是,所有其他时间它与System.out.println
在同一行。
代码:
//Create a scanner
Scanner input = new Scanner(System.in);
//Gets type
System.out.println("--Television Show or Film (t or f): ");
String type = input.nextLine();
input.close();
输出:
--Television Show or Film (t or f):
t
Desierd输出:
--Television Show or Film (t or f): t
感谢任何帮助。另外,我正在使用Eclipse Console。
答案 0 :(得分:5)
使用System.out.println
而不是{{1}}?
答案 1 :(得分:2)
尝试:
System.out.print("--Television Show or Film (t or f): ");
String type = input.next();
答案 2 :(得分:2)
原因是您使用println
System.out
版本的print
。仅使用System.out.print("--Television Show or Film (t or f): ");
:Sub FindMatches()
Dim oldrow As Integer
Dim newrow As Integer
For oldrow = 4 To 14
For newrow = 3 To 20
If Cells(oldrow, 12) = Cells(1, newrow) And Cells(oldrow, 13) = Cells(newrow, 1) Then 'date and brand
If Cells(1, 14) = Cells(newrow, 2) Then
Cells(newrow, 3).Value = Cells(oldrow, 14).Value ' m1
End If
If Cells(1, 15) = Cells(newrow + 1, 2) Then
Cells(newrow + 1, 3).Value = Cells(oldrow, 15).Value ' m2
End If
If Cells(1, 16) = Cells(newrow + 2, 2) Then
Cells(newrow + 2, 3).Value = Cells(oldrow, 16).Value ' m3
End If
If Cells(1, 17) = Cells(newrow + 3, 2) Then
Cells(newrow + 3, 3).Value = Cells(oldrow, 17).Value ' issue
End If
If Cells(1, 18) = Cells(newrow + 4, 2) Then
Cells(newrow + 4, 3).Value = Cells(oldrow, 18).Value ' repack
End If
If Cells(1, 19) = Cells(newrow + 5, 2) Then
Cells(newrow + 5, 3).Value = Cells(oldrow, 19).Value ' extra
End If
If Cells(1, 20) = Cells(newrow + 6, 2) Then
Cells(newrow + 6, 3).Value = Cells(oldrow, 20).Value ' wastage
End If
End If
Next newrow
Next oldrow
End Sub