Question

解析错误：语法错误，意外＆＃39; $ user＆＃39;第4行的C：\ xampp \ htdocs \ home \ login.php中的（T_VARIABLE）

    <?php

$host = "localhost"
$user = "root";    <------ line 4
$pass = "";
$db = "table";

mysql_connect($host, $user, $pass);
mysql_select_db($db);

if (isset($_POST['username'])) {
    $username = $_POST['username'];
    $password = $_POST['password']; 

    $sql = "SELECT * FROM users WHERE username='$username' AND password='$password'";
    $res = mysql_query($sql);

    if (mysql_num_rows($res) == 1) {
        echo "Super";
        exit();
    } else {
        echo "Siper";
        exit();
    }
}

?>

如何解决这个问题？

Answer 1

缺少分号：

 <?php

$host = "localhost"; <--- error :D
$user = "root";    <------ line 4
$pass = "";
$db = "table";

mysql_connect($host, $user, $pass);
mysql_select_db($db);

if (isset($_POST['username'])) {
    $username = $_POST['username'];
    $password = $_POST['password']; 

    $sql = "SELECT * FROM users WHERE username='$username' AND password='$password'";
    $res = mysql_query($sql);

    if (mysql_num_rows($res) == 1) {
        echo "Super";
        exit();
    } else {
        echo "Siper";
        exit();
    }
}

?>

Answer 2

你在第一行丢失了一个分号。请记住，在php中，错误通常是指周围所指定的行号，而不一定是行。 :)

即。

 $host = "localhost";

编辑：

您可能还需要清理$ _POST数据，或者重新考虑构建此数据的方式，否则您将对SQL注入保持开放状态。

请阅读此处了解更多信息： What's the best method for sanitizing user input with PHP?

PHP语法eroor

2 个答案: