Question

使用XmlDocument而不是XElement

Answer 1

不太清楚是什么让您选择XmlDocument而不是Linq到Xml。如果有选择，我更喜欢使用XDocument来处理Xml。

无论如何，您可以使用XmlDocument执行此操作。

public static string Stringify(XmlDocument doc)
{
    StringBuilder result = new StringBuilder();

    result.Append("ID=");

    foreach(XmlElement element in doc.GetElementsByTagName("var_name")) 
    {
        result.Append(element.GetAttribute("name"));

        foreach(XmlElement child in element.ChildNodes)
        {
            result.Append(string.Format(" {0}={1}", child.GetAttribute("ns"), child.GetAttribute("ps")));
        }
    }


    return result.ToString();
}

<强>输出继电器：

ID=name1 Desc=0 otp=0

选中此example

Answer 2

试试这个......

Usings

using System.Collections.Generic;
using System.IO;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

类

[XmlRoot(ElementName = "p")]
public class P
{
    [XmlAttribute(AttributeName = "ns")]
    public string Ns { get; set; }
    [XmlAttribute(AttributeName = "ps")]
    public string Ps { get; set; }
}

[XmlRoot(ElementName = "var_name")]
public class Var_name
{
    [XmlElement(ElementName = "p")]
    public List<P> P { get; set; }
    [XmlAttribute(AttributeName = "name")]
    public string Name { get; set; }
}

[XmlRoot(ElementName = "msg")]
public class Msg
{
    [XmlElement(ElementName = "var_name")]
    public Var_name Var_name { get; set; }
    [XmlAttribute(AttributeName = "id")]
    public string Id { get; set; }
}

代码

try
{
    XmlDocument xmlDoc = new XmlDocument();
    xmlDoc.Load("xml.xml");

    string XML = xmlDoc.InnerXml.ToString();
    byte[] BUFXML = ASCIIEncoding.UTF8.GetBytes(XML);
    MemoryStream ms1 = new MemoryStream(BUFXML);

    XmlSerializer DeserializerPlaces = new XmlSerializer(typeof(Msg));
    using (XmlReader reader = new XmlTextReader(ms1))
    {
        Msg dezerializedXML = (Msg)DeserializerPlaces.Deserialize(reader);

    }// Put a break-point here, then mouse-over dezerializedXML and you should have you values
}
catch (System.Exception)
{
    throw;
}
    }
}

该代码将获取您的xml（从与应用程序* .exe相同的文件夹中的xml.xml文件中读入）然后将其序列化为名为“dezerializedXML”的对象..... p>

使用XmlDocument而不是XElement

2 个答案: