我有以下结果数组:
Array
(
// 1st big array of results
[0] => Array
(
[0] => Array
(
[customer] => John
[shop_name] => shop1
[shop_address] => address1
)
[1] => Array
(
[customer] => John
[shop_name] => shop2
[shop_address] => address2
)
[2] => Array
(
[customer] => Mark
[shop_name] => shop1
[shop_address] => address1
)
)
// 2nd big array of results
[1] => Array
(
[0] => Array
(
[customer] => Cathy
[shop_name] => shop3
[shop_address] => address3
)
[1] => Array
(
[customer] => Cathy
[shop_name] => shop4
[shop_address] => address4
)
[2] => Array
(
[customer] => Maria
[shop_name] => shop3
[shop_address] => address3
)
)
)
每个大型结果中的每个客户都有{strong>唯一对 shop_name
和shop_address
。
我想做什么
我想将第一大数组的每个customer
放在一个<th></th>
中,而将其shop_name
和shop_address
放在个人<td></td>
中1}}像这样:
What I'd like to do - Table IMG
当然,重复第二大阵列的过程。
我是否拥有最佳的阵列结构?
或许我应该将每个customer
放在自己的数组中:
// Give each 'customer' its own array
foreach ($array[0] as $result) {
$array_by_customer[$result['customer']][] = $result;
}
但是你可以看到我只能为array[0]
- 第一大结果做到这一点。
答案 0 :(得分:0)
我认为你的方法很好:为每位顾客制作一个阵列。
我建议你对数组中的所有结果执行此操作,这就是它!
foreach ($array as $big_array_key => $results) {
foreach ($results as $result) {
$arrays_by_customer[$big_array_key][$result['customer']][] = $result;
}
}
然后你的$ arrays_by_customer将包含两个大数组:一个用于初始大数组。