我有一个NSObject boastObj,它包含string类型的购买属性。我正在通过JSON parse
检索值,这是结果的子对象。
@interface BoasterElite : NSObject
{
NSString* purchase;
}
以下是JSON。
"results": [
{
"name": "UserName",
"points": "2",
"profile_photo": "https:\/\/scontent.fblr1-1.fna.fbcdn.net\/hphotos-xtf1\/v\/t1.0-9\/12004045_134589590222520_1895675040105383396_n.jpg?oh=17c11a393c141443bdd3bc1451a560a8",
"purchase": [
{
"purchase_id": "1",
"purchase_type": "car",
"timeDate": "2016-04-01 00:10:49",
"brand": "Ferrari",
"model": "v3",
"year": "2016",
"photo": "https:\/\/cdn1.vox-cdn.com\/thumbor\/-pG8Dcb_qtRf6te3ug12FHhqUDs=\/1020x0\/cdn0.vox-cdn.com\/uploads\/chorus_asset\/file\/4156848\/Ferrari_F12tdf_3low.0.jpg",
"message": "ferrari car in boaster app",
"verify_id": "0"
}
]
}
],
答案 0 :(得分:0)
将json值存储在NSDictionary或NSArray中。
如果要检索NSString值,请使用
NSString *name = [[json objectForKey:@"results"] objectForKey:@"name"];
NSString *purchase_type = [[[json objectForKey:@"results"] objectForKey:@"purchase"] objectForKey:@"purchase_type"];
它可能对你有帮助。
答案 1 :(得分:0)
results
是一个字典数组,假设json
是JSON对象
NSArray *results = json["results"];
您可以使用
获取points
值
NSString *points = results[0]["points"];
purchase
位于数组的第一项,它也是一个字典数组。
NSArray *purchases = results[0]["purchase"];
NSDictionary *purchase = purchases[0];
现在您可以按键获取值,例如
NSString *brand = purchase["brand"];