Question

我有令牌的内容，并且想要删除所有不以测试开头的令牌。例如，我有内容：

$content = 'Hello [test:username]. What are you [token:name]';
$string = preg_replace('/\[test(.*)\]/', '', $content);

这项工作，但用空字符串替换所有以测试开头的标记。我希望与测试 无法启动相反，并替换所有其他内容。我应该如何改变正则表达式。我想在preg_replace之后得到这个结果：

$content = 'Hello [test:username]. What are you';

Answer 1

您可以使用以下正则表达式

(?:\[test:[^]]+\])(*SKIP)(*F)|(?:\[\w[^]]+\])

所以你的代码看起来像

preg_replace('/(?:\[test:[^]]+\])(*SKIP)(*F)|(?:\[\w[^]]+\])/', '', $content);

<强>解释

(?:\[test:[^]]+\]) // Will capture a group of tokens that have same 
                      pattern like as [test:...]

(*SKIP)(*F)        // This is supported by PCRE to skip the above captured group 

|(?:\[\w[^]]+\])   // This'll capture rest of the group that doesn't 
                     contains pattern like as [test:...]

Php preg_replace - 正则表达式（删除令牌）

1 个答案: