我正在以表格形式加载数据。我想只允许用户在表单有效时提交数据。最初形式是原始但无效。在用户可以编辑的三个字段中,如果他改变了任何一个,那么表单就不再是原始状态了,这是好的但是表单仍然无效......尽管其他字段中的值是有效的。我怎样才能绕过每个字段放置一个isPristine和IsValid条件?代码如下。我把它放在转发器里面进行编辑/查看。删除了代码的视图部分,因为我认为它在这种情况下不适用。
<table class="table">
<tbody>
<tr ng-repeat="comment in comments | orderBy: 'CreatedDate':true" ng-class-odd="'odd'" ng-class-even="'even'">
<td style="padding-left:1em;">
<ng-form name="editCommentForm">
<table border="0" class="form-group" ng-show="editComment.CommentID == comment.CommentID">
<tr>
<td width="25%">Comment Type:</td>
<td width="50%">
<select name="cbCommentType" ng-model="comment.CommentTypeID" required>
<option ng-selected="{{comment.CommentTypeID == option.CommentTypeID}}" ng-repeat="option in CommentTypes" value="{{option.CommentTypeID}}">{{option.Name}}</option>
</select>
</td>
<td width="25%" class="errorMessage">
<span ng-show="editCommentForm.cbCommentType.$error.required">Type is required.</span>
</td>
</tr>
<tr>
<td colspan="3"> </td>
</tr>
<tr>
<td width="25%">Effective Date:</td>
<td width="50%">
<span class="input-group">
<input type="text" name="txtEffectiveDate" class="form-control" uib-datepicker-popup ng-model="comment.EffectiveDate" is-open="editComment.popupOpened" ng-required="true" close-text="Close" />
<span class="input-group-btn">
<button type="button" class="btn btn-default" ng-click="openDatePicker(comment)"><i class="glyphicon glyphicon-calendar"></i></button>
</span>
</span>
</td>
<td width="25%" class="errorMessage">
<p ng-show="editCommentForm.txtEffectiveDate.$error.required">Effective date is required.</p>
</td>
</tr>
<tr>
<td colspan="3"> </td>
</tr>
<tr>
<td width="25%">Comment:</td>
<td width="50%">
<textarea name="txtComment" style="width:80%;resize:none;" name="txtComment" ng-model="comment.CommentText" placeholder="add comment here" ng-minlength="4" required> </textarea>
</td>
<td width="25%" class="errorMessage">
<p ng-show="editCommentForm.txtComment.$error.required">Comment is required.</p>
<p ng-show="editCommentForm.txtComment.$error.minlength">Comment is too short.</p>
</td>
</tr>
<tr>
<td colspan="3" align="center">
<input type="button" value="Cancel" ng-click="cancelObj(comment)" class="btn btn-default active btn-xs" />
<input type="button" ng-disabled="editCommentForm.$pristine ? false : editCommentForm.$invalid" value="Save comment" ng-click="updateObj(comment)" class="btn btn-default active btn-xs" />
</td>
</tr>
</table>
</ng-form>
</td>
</tr>
</tbody>
</table>
答案 0 :(得分:2)
你有1个表格,你有3个字段。
您可以让控制器访问该表单。
通常,为此,我使用CONTROLLER AS语法如下:
<ng-form name="vm.editCommentForm">
其中vm是控制器别名。
(我确信它也可以在没有CONTROLLER AS语法的情况下将表单暴露给控制器,但这是为了让你弄清楚是否对这种方法感兴趣。)
然后在你的控制器中你会做类似......
vm.showFieldError = function(fieldName) {
var formField = vm.editCommentForm[fieldName];
return (formField.$invalid && formField.$dirty);
}
然后您将在视图中引用此函数以确定是否显示错误消息。