Question

我有从下列算法（伪代码）制作Java代码方法的任务：

Design Algorithm CalcLowest 
var lowest = first value in the array numList 
For index=1 to count-1 
If value at index is less than lowest 
Set lowest to value at index 
End if
End loop 

Design Algorithm CalcHighest 
var highest = first value in the array numList 
For index=1 to count-1 
If value at index is greater than highest 
Set highest to value at index 
End if 
End loop

我写了以下内容：

public int getHighest()
    {   
        int highest = marks[0];

        for (int i=0; i < count +1; i++){

            if(i > highest)

                highest = i;}

        return highest;

        }

 public int getLowest()
    {
           int lowest = marks[0];

           for (int i=0; i < count +1; i++){


               if(i < lowest)

                   lowest = i;}

           return lowest;

           }

    }

它会运行，但最高值始终为5，最低值始终为0.为什么？

Answer 1

您正在将i与最低

进行比较

public ImagePanel(String imgpath) throws IOException{
try {
    image = ImageIO.read(new File(imgpath));
catch (IOException e) {
    // handle exception
    throw new IOException();
    }
}

每次循环时我都会递增。因此，最低和最高将始终与您循环的次数相同。

而不是与i比较，与数组中位置编号i 的值进行比较。

为什么我从算法实现中得到错误的结果？

1 个答案: