Question

我正在开发一个使用JTOpen ProgramCall类（com.ibm.as400.access.ProgramCall）在IBM i（AS / 400）上调用程序的Web应用程序（在Tomcat上运行）。我的问题是程序调用需要超过30秒才能响应，这会触发Sub Document_Standards() ' ' Document_Standards Macro ' ' ActiveWindow.View = xlPageLayoutView Selection.Font.Size = 12 Selection.Font.Size = 14 Selection.Font.Bold = True Application.PrintCommunication = False With ActiveSheet.PageSetup .LeftHeader = "" .CenterHeader = "&""-,Bold""&14&F" .RightHeader = "" .LeftFooter = "Created by Chris" .CenterFooter = "CONFIDENTIAL" .RightFooter = "Printed on Date ()" .LeftMargin = Application.InchesToPoints(0.7) .RightMargin = Application.InchesToPoints(0.7) .TopMargin = Application.InchesToPoints(0.75) .BottomMargin = Application.InchesToPoints(0.75) .HeaderMargin = Application.InchesToPoints(0.3) .FooterMargin = Application.InchesToPoints(0.3) .Zoom = 100 .PrintErrors = xlPrintErrorsDisplayed .OddAndEvenPagesHeaderFooter = False .DifferentFirstPageHeaderFooter = False .ScaleWithDocHeaderFooter = True .AlignMarginsHeaderFooter = True .EvenPage.LeftHeader.Text = "" .EvenPage.CenterHeader.Text = "" .EvenPage.RightHeader.Text = "" .EvenPage.LeftFooter.Text = "" .EvenPage.CenterFooter.Text = "" .EvenPage.RightFooter.Text = "" .FirstPage.LeftHeader.Text = "" .FirstPage.CenterHeader.Text = "" .FirstPage.RightHeader.Text = "" .FirstPage.LeftFooter.Text = "" .FirstPage.CenterFooter.Text = "" .FirstPage.RightFooter.Text = "" End With Application.PrintCommunication = True ActiveSheet.Shapes.Range(Array("Picture 1")).Select End Sub。

此类有一个java.net.SocketTimeoutException: Read timed out exception方法，但它似乎对套接字超时没有影响。我还检查了我的Tomcat配置，但没有看到任何会导致此行为的内容。

有没有人知道改变这种实现的超时的方法？

代码：

setTimeout()

Answer 1

好吧，经过几个小时后，我找到了解决方案。显然，原始开发人员在JDBC连接字符串中添加了一个socket timeout参数 - 只需删除参数即可，默认值为0，或无限超时。

在：

String connectionStr = "jdbc:as400://" + systemInfo.getIPAddress() + ":1527" + ";naming=system;socket timeout=30000;thread used=false;errors=full;prompt=false;date format=iso;block size=128;transaction isolation=none;user=" + systemInfo.getUserName() + ";password=" + systemInfo.getPassword();

后：

String connectionStr = "jdbc:as400://" + systemInfo.getIPAddress() + ":1527" + ";naming=system;thread used=false;errors=full;prompt=false;date format=iso;block size=128;transaction isolation=none;user=" + systemInfo.getUserName() + ";password=" + systemInfo.getPassword();

：\

JTOpen ProgramCall套接字超时

1 个答案: