我试图根据窗口大小将对象放在随机位置。
LayoutRoot
是其所在网格的名称。
//Give Dot a random position
int left = random.Next(LayoutRoot.MinWidth, LayoutRoot.MaxWidth);
int top = random.Next(-900, 900);
Dot.Margin = new Thickness(left, top, 0, 0);
LayoutRoot.MinWidth&的错误MaxWidth:Cannot convert double to int
尝试
//Give Dot a random position
double left = random.NextDouble(LayoutRoot.MinWidth, LayoutRoot.MaxWidth);
double top = random.Next(-900, 900);
Dot.Margin = new Thickness(left, top, 0, 0);
NextDouble出错:Method NextDouble takes 2 arguments
答案 0 :(得分:0)
这可能有效。
double mWidth = LayoutRoot.MinWidth;
double mxWidth = LayoutRoot.MaxWidth;
double left = random.NextDouble(mWidth, mxWidth);
double top = random.Next(-900, 900);
Dot.Margin = new Thickness(left, top, 0, 0);
}
答案 1 :(得分:0)
好好再试一下这个。修改了你的代码。此代码不假定任何预定义的高度或宽度,它根据LayoutRoot
的当前大小得到。它还会抵消Dot
大小,因此它不会从屏幕上掉下来。
MainWindow.xaml
<Window x:Class="WpfApplication1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApplication1"
mc:Ignorable="d"
Title="MainWindow" Height="350" Width="525">
<Grid x:Name="LayoutRoot">
<Ellipse Width="2" Height="2" Fill="Black" x:Name="Dot"></Ellipse>
</Grid>
</Window>
MainWindow.xaml.cs
using System;
using System.Windows;
namespace WpfApplication1
{
public partial class MainWindow
{
private static Random random = new Random();
public MainWindow()
{
InitializeComponent();
// Don't move dot until the window is loaded, not necessary but generally you don't want to hold up the window from displaying.
this.Loaded += OnLoaded;
}
private void OnLoaded(object sender, RoutedEventArgs routedEventArgs)
{
// The farthest left the dot can be
double minLeft = 0;
// The farthest right the dot can be without it going off the screen
double maxLeft = LayoutRoot.ActualWidth - Dot.Width;
// The farthest up the dot can be
double minTop = 0;
// The farthest down the dot can be without it going off the screen
double maxTop = LayoutRoot.ActualHeight - Dot.Height;
double left = RandomBetween(minLeft, maxLeft);
double top = RandomBetween(minTop, maxTop);
Dot.Margin = new Thickness(left, top, 0, 0);
}
private double RandomBetween(double min, double max)
{
return random.NextDouble() * (max - min) + min;
}
}
}
答案 2 :(得分:0)
也许这会有所帮助,这是一个关于在画布上设置随机点的问题,也许可以调整以满足您的需求wpf-rendering-a-canvas-at-random-points
答案 3 :(得分:0)
因此,在查看了凯利给出的答案后,我遇到了类似的问题,即对象在加载后将不会显示。我的目标是让应用程序的欢迎屏幕每10秒随机移动一次。因此,按照他的设计,存在一个问题,因为由于缺乏列/行定义,网格没有实际长度,因此我们不得不在每次尝试随机化时都强制应用重新计算大小。
这是我使用的XAML:
<Grid x:Name="LayoutRoot">
<TextBlock x:Name="WelcomeTextBlock"
Height="200"
Style="{StaticResource WelcomeTextBlock}">
Welcome!
</TextBlock>
<Ellipse Width="2" Height="2" x:Name="Dot"/>
</Grid>
更重要的是后面的实际代码:
public partial class WelcomePage : Page
{
private static Random Rnd = new Random();
private static DispatcherTimer _timer;
public WelcomePage()
{
InitializeComponent();
this.Loaded += OnLoaded;
this.Unloaded += OnClosing;
}
private void OnLoaded(object sender, RoutedEventArgs args)
{
this.LayoutRoot.Margin = GetNewMargin();
_timer = new DispatcherTimer {Interval = TimeSpan.FromSeconds(5)};
_timer.Tick += MoveWelcome;
_timer.Start();
}
private void MoveWelcome(object sender, EventArgs e)
{
this.LayoutRoot.Margin = GetNewMargin();
}
private Thickness GetNewMargin()
{
this.Measure(new Size(double.PositiveInfinity, double.PositiveInfinity));
this.Arrange(new Rect(0, 0, this.DesiredSize.Width, this.DesiredSize.Height));
var maxLeft = this.LayoutRoot.ActualWidth - Dot.Width;
var maxTop = LayoutRoot.ActualHeight - Dot.Height;
var left = RandomBetween(0, maxLeft);
var top = RandomBetween(0, maxTop);
return new Thickness(left, top, 0 ,0);
}
private static void OnClosing(object sender, RoutedEventArgs args)
{
_timer.Stop();
}
private static double RandomBetween(double min, double max) => Rnd.NextDouble() * (max - min) + max;
除计时器功能外,这里的主要变化是,在计算页边距厚度时,我们强制窗口,或者在我的情况下,页面会更新屏幕尺寸并正确安排项目。