我尝试从两个不同的表中选择所有列WHERE active = 1
我有2个表 table_pro 和 table_basic ,
sql:"select * from table_basic,table.name";
和2条件:
- WHERE active = 1
- WHERE table_pro.id = table_basic.name.id
醇>
如何正确使用
这是table_pro
+----+--------+---------+-----------+
| id | people | rooms | active |
+----+--------+---------+-----------+
| 1 | 5 | 10 | 0 |
| 2 | 12 | 17 | 0 |
| 3 | 21 | 38 | 1 |
+----+--------+---------+-----------+
这是table_basic
+---------+-------+---------+------------+----------+
| name_id | name | balance | title | time |
+---------+-------+---------+------------+----------+
| 1 |shop | 100 | failed | 15:10:20 |
| 2 |factory| 75 | error | 15:10:20 |
| 3 |studio | 25 | timed_out | 15:10:20 |
+---------+-------+---------+------------+----------+
我希望此输出结果只有行(来自所有列),状态为active = 1
+-----+-------+----- --+--------+-------+----------+---------+--------+
| id | people| rooms | name |balance| title | time | active |
+-----+-------+--------+--------+-------+----------+---------+--------+
| 3 | 21 | 38 | studio |25 | timed_out| 15:10:20| 1 |
+-----+-------+--------+--------+-------+----------+---------+--------+
由于
答案 0 :(得分:1)
SELECT A.id, A.people, A.rooms, B.name, B.balance, B.title, B.time, A.active
FROM
table_pro AS A
JOIN
table_basic AS B
ON
A.id = B.name_id
WHERE
A.id = 3
答案 1 :(得分:0)
SELECT table_pro.*, table_basic.*
FROM table_pro
INNER JOIN table_basic
ON table_basic.name_id = table_pro.id
WHERE table_pro.active = 1